Need help with linear independence proof

dyanmcc
Messages
7
Reaction score
0
Hi,

I don't know how to do the following proof:

If (v1, ...vn) are linearly independent in V, then so is the list (v1-v2, v2-v3, ...vn-1 -vn, vn).

I can do the proof if I replace 'linearly independent' with 'spans V' ...so what connection am I missing?

Thanks much!
 
Physics news on Phys.org
Prove it by contradiction. If the second set of vectors was not linearly independent, then you can write 0 as a linear combination of those vectors. Then simply expand out each vector to show that this implies v1...vn are also linearly dependent.
 
Great thanks. Here's another one for you...Prove that if V is finite dimensional with dim V > 1, then the set of noninvertible operators on V is not a subspace of L(V)
 
What have you done for that second problem dyanmcc? Start by thinking about matrices.
 
0rthodontist said:
Prove it by contradiction. If the second set of vectors was not linearly independent, then you can write 0 as a linear combination of those vectors. Then simply expand out each vector to show that this implies v1...vn are also linearly dependent.
Also be sure to prove that there is still a nonzero coefficient when you expand the vectors out. (look at the FIRST nonzero coefficient before expansion)
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
2
Views
3K
Replies
4
Views
2K
Replies
14
Views
3K
Replies
3
Views
8K
Replies
1
Views
1K
Replies
12
Views
3K
Back
Top