Need help with some aspects of Bell’s theorem

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Looking for the help with a conceptual framework of the Bell’s theorem and would appreciate any assistance.

The Bell theorem has been verified in numerous experiments (lets assume that those experiments are free form loopholes).

As I understand the essence of those proves are based on comparing correlations predicted by QM with the correlations derived from the hidden variables theories and after ruling them out, the QM (non-locality) is the only option.

If the above makes a sense, should these hidden variables theories have some prerequisites to be used in the Bell theorem? Should they be in compliance with QM equations and yield the same experimental results as predicted by QM. If they don’t complies with QM, they are not real hidden variables (QM) theories but surrogatess only.

If these theories indeed comply with QM prerequisites , why their correlations aren’t calculated based on the QM prediction, but the ‘classical’ approach is used instead?
 
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miosim said:
the essence of those proves are based on comparing correlations predicted by QM with the correlations derived from the hidden variables theories and after ruling them out, the QM (non-locality) is the only option.

Yes.

miosim said:
Should they be in compliance with QM equations and yield the same experimental results as predicted by QM.

No; that's the whole point of Bell's theorem. Bell's theorem says that it is impossible to have a local hidden variable theory that makes the same predictions for experimental results as QM. That's why the experimental proofs rule out hidden variable theories: the experiments show that the predictions of QM are correct, so any theory that makes different predictions--and Bell's theorem says any local hidden variable theory must make different predictions--is ruled out by experiment.

In your terminology, Bell's theorem says that it is impossible to have a local hidden variable theory that "complies with QM prerequisites".
 
miosim said:
Looking for the help with a conceptual framework of the Bell’s theorem and would appreciate any assistance.

The Bell theorem has been verified in numerous experiments (lets assume that those experiments are free form loopholes).

As I understand the essence of those proves are based on comparing correlations predicted by QM with the correlations derived from the hidden variables theories and after ruling them out, the QM (non-locality) is the only option.

If the above makes a sense, should these hidden variables theories have some prerequisites to be used in the Bell theorem? Should they be in compliance with QM equations and yield the same experimental results as predicted by QM. If they don’t complies with QM, they are not real hidden variables (QM) theories but surrogatess only.

If these theories indeed comply with QM prerequisites , why their correlations aren’t calculated based on the QM prediction, but the ‘classical’ approach is used instead?

miosim, I will give you a short reply but will otherwise bow out to allow others to answer you. I don't believe I have been effective in getting the message across on this subject in earlier threads. Hopefully, the following will help a little.
----------------------------------------------------------

With Bell, you MUST distinguish between LOCAL hidden variable theories and NON-LOCAL ones. You didn't do that above, and it makes it nearly impossible to answer your questions. Here is the summary:

1. LOCAL HV theories are incompatible with QM and Bell tests.
2. Bell tests do NOT prove NON-LOCALITY. They prove what is call QUANTUM NON-LOCALITY.
3. The reason for this different term (with Quantum added) is that there are LOCAL NON-REALISTIC theories that are QUANTUM NON-LOCAL. That may seem like a contradiction, but it is not.
4. There are many interpretations of QM that display Quantum Non-locality. They include: Copenhagen, Bohmian, Many Worlds, Time Symmetric, etc. All of these predict as per orthodox QM. So all of these are either NON-LOCAL or NON-REALISTIC (or both).
5. The observed correlations in Bell tests are not as predicted by classical statistics, so that approach is discarded completely when calculating the predictions. As you can see from the graph you presented previously, a classical approach to the statistics does not even come close to the actual results. The other approach is what is sometimes called semi-classical. That approach is closer to actual, but is still ruled out.

Good luck,

-DrC
 
PeterDonis said:
Bell's theorem says that it is impossible to have a local hidden variable theory that makes the same predictions for experimental results as QM

This is exactly what I can't grasp, doesn't matter how references I read.

I thought that Bell (and other) select some generic candidate for hidden variable theory and applying some sort of classical approach (foreign for the QM system) calculate correlation.
As I understand the REAL hidden variable theory should have the same predictions as orthodox QM but only having different interpretation of the observable results. Therefore it may not be fair to calculate correlation not deriving from QM.
 
miosim said:
I thought that Bell (and other) select some generic candidate for hidden variable theory and applying some sort of classical approach (foreign for the QM system) calculate correlation.

First, as DrChinese noted, you need to carefully distinguish between local hidden variable theories and nonlocal hidden variable theories. Bell's Theorem only applies to local ones.

What Bell did was to show that any local hidden variable theory must have certain properties that restrict the correlations it can predict; and that the correlations predicted by QM are outside those restrictions. He didn't pick any particular local hidden variable theory, not even a "generic candidate"; he just used general properties that any local hidden variable theory must have.

miosim said:
As I understand the REAL hidden variable theory should have the same predictions as orthodox QM

It's perfectly possible for a nonlocal hidden variable theory to make the same predictions as QM. An example of such a theory is the De Broglie-Bohm pilot wave theory. But it's not possible for a local hidden variable theory to make the same predictions as QM. So one way of stating the conclusion of Bell's Theorem is that, if you want the "real" hidden variable theory to make the same predictions as QM, it has to be nonlocal.
 
Thank you for both of you, it helps to focus .

Dr. DrChinese

I am back reading tutorials on your site ...

http://drchinese.com/David/Bell_Theorem_Easy_Math.htm

... but stumble on the following sentence:

“…Suppose we consider a single particle (photon) of light. We ask a simple question: does it have a definite polarization at the following three angles: 0 degrees (A), 120 degrees (B), and 240 degrees (C)? According to the EPR paper, its polarization at these 3 angles correspond to actual elements of reality…”

My question is: How a single photon may have “definite polarization at the THREE angles”?
 
miosim said:
My question is: How a single photon may have “definite polarization at the THREE angles”?

I gess you mean that according to EPR a single photon have definite polarization regardless of the angle of polarizer.
 
miosim said:
I gess you mean that according to EPR a single photon have definite polarization regardless of the angle of polarizer.

Exactly! In other words: your car (if you have one :) ) has a length, a height, and a width at all times. Does a photon? Obviously photons do not have a length, a height, or a width. But do they have a polarization at 0, 120, 240 degrees at one point in time (simultaneously) ?

The EPR ipremise was that they did. (And you could call that a "semi-classical" idea because it would match the perfect correlations they expected for entangled systems. Please note that "semi-classical" has somewhat different meanings to different people in QM concepts.) In other words, EPR did not deny entanglement as phenomenon. They envisioned a day in which such a theory could be formulated (it never was of course).

So EPR ASSUMED realism (elements of reality) but could not prove it rigorously. Bell formulated a challenge to that assumption.
 
PeterDonis said:
What Bell did was to show that any local hidden variable theory must have certain properties that restrict the correlations it can predict;

For a given experimental setup, this restriction can usually be described using an inequality relation for the quantity being measured. This is often called a Bell inequality.

and that the correlations predicted by QM are outside those restrictions.

That is, the predictions of QM violate the Bell inequality for the experiment in question; whereas the predictions of any local realistic theory must satisfy that inequality. To date all experiments of this type have violated their Bell inequality.
 
  • #10
DrChinese said:
But do they have a polarization at 0, 120, 240 degrees at one point in time (simultaneously)

I think this sentence may confuse reader, because I read it as the 'same photon may have 3 different polarizations (simultaneously) prior interacting with polarizer'.

I have other difficulties to read explanations on your site, but I don't want to "bug" this thread with my silly questions about every sentence.

I understand all comments provided so far, but I feel I need go back to reading and than I may have a better question.

Thank you all
 
  • #11
miosim said:
I think this sentence may confuse reader, because I read it as the 'same photon may have 3 different polarizations (simultaneously) prior interacting with polarizer'.

You don't think it strange that any ordinary object has a length/width/height, but have a hard time imagining polarizations at 3 angles? EPR imagined the extra attributes existed (of course I follow QM which does not support that).

Different sites use different words, and that may help you too.
 
  • #12
miosim said:
I think this sentence may confuse reader, because I read it as the 'same photon may have 3 different polarizations (simultaneously) prior interacting with polarizer'.

You should read that as "the photon may be in a state such that if I measure the polarization at a given angle I will get a particular result". A three-dimensional object works that way - I can say that if I measure its height I'll get some number, if I measure its width I'll get some number, if I measure its length I'll get some number. We call these three numbers the height, width, and length respectively, and we have no problem saying that the object has definite height, width, and length whether we make the measurement or not.

Quantum mechanical measurements don't work that way. The formalism of QM says that if we don't measure something then it doesn't have a definite value (not "it has a value but we don't know what it is because we didn't measure it"). Bell's theorem says that any assignment of definite values to these unmeasured quantities will, under some circumstances, lead to results that differ from the quantum mechanical prediction.
 
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  • #13
PeterDonis said:
First, as DrChinese noted, you need to carefully distinguish between local hidden variable theories and nonlocal hidden variable theories. Bell's Theorem only applies to local ones.

What Bell did was to show that any local hidden variable theory must have certain properties that restrict the correlations it can predict; and that the correlations predicted by QM are outside those restrictions. He didn't pick any particular local hidden variable theory, not even a "generic candidate"; he just used general properties that any local hidden variable theory must have.
It's perfectly possible for a nonlocal hidden variable theory to make the same predictions as QM. An example of such a theory is the De Broglie-Bohm pilot wave theory. But it's not possible for a local hidden variable theory to make the same predictions as QM. So one way of stating the conclusion of Bell's Theorem is that, if you want the "real" hidden variable theory to make the same predictions as QM, it has to be nonlocal.

EPR assumed realism but the conclusion for the inequality violation is usually non - locality. Why not non realism alone ?
What would be a real (complete) local non realism hidden variable model that would make same predictions as QM ?
Besides the many worlds interpretation.
 
  • #14
morrobay said:
EPR assumed realism but the conclusion for the inequality violation is usually non - locality.

That's because Bell used the assumption of locality to derive his theorem; he didn't use any assumption of "realism". AFAIK the MWI, since it's just an "interpretation" of QM and makes all the same predictions, violates the locality assumption as well, at least as Bell formulated it.
 
  • #15
Nugatory said:
Bell's theorem says that any assignment of definite values to these unmeasured quantities will, under some circumstances, lead to results that differ from the quantum mechanical prediction.

I am trying to understand why it happens. What are the KEY physical characteristics of any deterministic LV theories that case a lower correlation compare to correlations derived from QM?

I wonder if the difference is as follow: in the deterministic model the spin/polarization are not affected by position of detectors, but according to QM the position of detectors influences (positively?) the result of measurement thus causing a higher correlation.
(see below Bell's article "On the E...P...R... paradox (1964) describing the deterministic LV model: "The vital assumption for this model is that the result of measurement B doesn't depend on setting of detectors."

https://www.physicsforums.com/attachments/74296

PeterDonis said:
It's perfectly possible for a nonlocal hidden variable theory to make the same predictions as QM. An example of such a theory is the De Broglie-Bohm pilot wave theory.
It seams that Broglie–Bohm theory (see quote from Wiki below) has the same prediction as QM because according to this theory the measurement device is also influences the particle's property (spin, polarization, etc.) and thus increases (compare to deterministic model) correlation. Does it make sense?

http://en.wikipedia.org/wiki/De_Broglie%E2%80%93Bohm_theory
Thus, for the de Broglie–Bohm theory, the particle's spin is not an intrinsic property of the particle—instead spin is, so to speak, in the wave function of the particle in relation to the particular device being used to measure the spin.
 
  • #16
miosim said:
I am trying to understand why it happens. What are the KEY physical characteristics of any deterministic LV theories that case a lower correlation compare to correlations derived from QM?

I wonder if the difference is as follow: in the deterministic model the spin/polarization are not affected by position of detectors, but according to QM the position of detectors influences (positively?) the result of measurement thus causing a higher correlation.
(see below Bell's article "On the E...P...R... paradox (1964) describing the deterministic LV model: "The vital assumption for this model is that the result of measurement B doesn't depend on setting of detectors."
Yes, that's pretty much it. Bell's proof proceeds from the assumption that the probability distribution of the measurement at a detector can be written as a function of the initial state of the entangled pair and the setting of that detector, but not the setting of the other detector. That's pretty much the operational definition of a local theory, and altogether consistent with EPR's sense of locality.

It seams that Broglie–Bohm theory (see quote from Wiki below) has the same prediction as QM because according to this theory the measurement device is also influences the particle's property (spin, polarization, etc.) and thus increases (compare to deterministic model) correlation. Does it make sense?
The dBB theory is indeed non-local in this sense, and thus is capable of reproducing the QM predictions and experimental results. It's a matter of personal taste and an endless interpretational rathole whether it is strictly correct that the measuring device "influences the particle's property"; the most that you can say without slipping in some additional assumptions is that the settings of the measuring devices influence the correlation of the results of the measurements.
 
  • #17
Nugatory said:
Bell's proof proceeds from the assumption that the probability distribution of the measurement at a detector can be written as a function of the initial state of the entangled pair and the setting of that detector, but not the setting of the other detector.

Do you mean that per QM (and not per deterministic model) the measurement at a closest detector can be written as a function of the initial state of the entangled pair and the setting of that detector, while the second (more distal) detector interacts with the particle that lost entanglements?
 
  • #18
miosim said:
Do you mean that per QM (and not per deterministic model) the measurement at a closest detector can be written as a function of the initial state of the entangled pair and the setting of that detector, while the second (more distany) detector interacts with the particle that lost entanglements?

No I do not mean that. It's easy to set up thought experiments in which the distances to the detectors and hence the relative ordering of the two observations is different for different observers, so there is no meaningful way of saying that one particle interacts before the other. The quantum mechanical prediction is that the after you've done both measurements, in either order, they will be correlated; bell's theorem says this correlation will have statistical properties that cannot be reproduced by any theory in which the probability distribution of results at one detector is not a function of, among other things, the setting of the other detector.
 
  • #19
Nugatory said:
It's easy to set up thought experiments in which the distances to the detectors and hence the relative ordering of the two observations is different for different observers, so there is no meaningful way of saying that one particle interacts before the other.

Say we set up a thought experimentscase of entangled photons, in which the first detectors is just few meters away from the experimenter, while the second detectors is on Mars. Would the experimenter receive the results of measurement from the first detector in a few nanoseconds instead of few minutes (time that light travel to Mars)?
This question is not about Bell correlation but about QM in general. Is the photon that will reach the detector on Mars will be still entangled?
 
  • #20
PeterDonis said:
That's because Bell used the assumption of locality to derive his theorem; he didn't use any assumption of "realism".

Don't mean to be contradictory, but...

Bell did not identify the spot where he introduced realism... but he did introduce it and I can show you where. Look at his original paper. His (2) is the locality condition, and then after his (14) he makes the leap to a THIRD element of reality (in addition to a and b): "It follows that c is another unit vector..." This is referenced in EPR when they say that they assume that elements of reality that individually must exist (height/length/width are our examples of simultaneous realism in this thread) must also exist simultaneously. Bell is making the mathematical implementation of that statement by mixing a, b and c in the next few equations. (QM of course would reject all this, either (2) or (14+) or both.)
 
  • #21
miosim said:
Say we set up a thought experimentscase of entangled photons, in which the first detectors is just few meters away from the experimenter, while the second detectors is on Mars. Would the experimenter receive the results of measurement from the first detector in a few nanoseconds instead of few minutes (time that light travel to Mars)?
This question is not about Bell correlation but about QM in general. Is the photon that will reach the detector on Mars will be still entangled?

Nugatory answered that and you quoted his answer: there is no relevance to the ordering or the distance involved. You can make any deductions you like from that, because QM makes no further statement about it at all.
 
  • #22
DrChinese said:
Nugatory answered that and you quoted his answer: there is no relevance to the ordering or the distance involved. You can make any deductions you like from that, because QM makes no further statement about it at all.

OK, fair enough.
 
  • #23
miosim said:
Say we set up a thought experiment case of entangled photons, in which the first detectors is just few meters away from the experimenter, while the second detectors is on Mars. Would the experimenter receive the results of measurement from the first detector in a few nanoseconds instead of few minutes (time that light travel to Mars)?
yes, but an observer aboard a spaceship flying through the solar system at sufficient speed will find that the detector on Mars triggers before the one on earth. Both observers are equally correct, and there is no way to claim that one order of detections is more real or right than the other. You'll have to learn some special relativity to understand what's going on here - google for "relative of simultaneity" and "space-like separation".
This question is not about Bell correlation but about QM in general. Is the photon that will reach the detector on Mars will be still entangled?
In QM it makes no sense to talk about the time in between the two measurements, nor about a single member of a pair being entangled. Entanglement is a statement about the results of two measurements, after they've both been made - and nothing more.
 
  • #24
Nugatory said:
but an observer aboard a spaceship flying through the solar system at sufficient speed will find that the detector on Mars triggers before the one on earth.

I think I have a general understanding of this concept. However for an observer who is in the same time reference as Earth or Mars and taking in account comparatively small difference in speed between Earth and Mars - would the time dilution will be too small to "wash out" the difference between nanoseconds and minutes ?
 
  • #25
I actually don't concern much about "space-like separation" question and is satisfied with your answer and the fact that "QM makes no further statement about it at all"

I am glad to see the light in the end of a tunnel called Bell's theorem. I will have few more questions but first I need to do some homework.

Thank you all for help.
 
  • #26
miosim said:
I think I have a general understanding of this concept. However for an observer who is in the same time reference as Earth or Mars and taking in account comparatively small difference in speed between Earth and Mars - would the time dilution will be too small to "wash out" the difference between nanoseconds and minutes ?
There will be some observers for whom the detection on Earth "obviously" happens first, and they'll be the ones who are more or less at rest relative to Earth and Mars - Mars is moving at several kilometers per second relative to earth, but compared with the speed of light that's nothing.

There will be other observers for whom the detection on Mars just as "obviously" happens first, and they'll be the ones who are flying past the solar system at a relative speed that's very close to that of light.

There is no way that you can arrange the two detectors so that all observers everywhere in the universe will agree about which one happened first. That's the significance of the "space-like separation" that I suggested you google for earlier.
 
  • #27
I am still troubled with how Bell theorems treats the Local Hidden Variable (LHV) theories by reducing them to classical objects, like magnets, socks, boxes, etc.

J. S. Bell, “Bertlmann’s socks and the nature of reality” 1981
“.. We formulated these considerations first for pairs of socks, moving with considerable confidence in those familiar objects. But why not reason similarly for the pairs of particles of the EPR experiment? …”

My answer to this rhetorical question would be: - no, because in general we should not use the same reasoning for classical objects (socks, magnets, etc.) and for quantum entities (as LHV models are).

Lets continuer with this Bell’s paper:

General argument.
So the following argument will not mention particles, nor indeed fields, nor any other particular picture of what goes on at the microscopic level. Nor will it it involve any use of the words "quantum mechanical system", which can have an unfortunate effect on the discussion. The difficulty is not created by any such picture or any such terminology. It is created by the predictions about the correlations in the visible outputs of certain conceivable experimental set-ups. Consider the general experimental set-up of figure. …”


Following these lines, the LHV model, striped from all quantum and even physical “privileges”, was used to calculate correlation based on the formal logic of socks and boxes. Eventually this “stripped to bones” LHV model was extended to All LHV models and eventually was “successfully” stricken down because it does not match with experiment.

OK, let's be a little more creative with LHV and conceder one that incorporates the “algorithm” that assists photon passing polarizer (or any other obstacle). The example of such type of “algorithms” is principle of minimal action and principle of minimum free energy, etc.

Could the correlation for such LHV model match with correlation for QM model?
 
  • #28
miosim said:
OK, let's be a little more creative with LHV and conceder one that incorporates the “algorithm” that assists photon passing polarizer (or any other obstacle). The example of such type of “algorithms” is principle of minimal action and principle of minimum free energy, etc.

Could the correlation for such LHV model match with correlation for QM model?

No, not as long as it is local. You will notice that Bell's ##\lambda## is a very general construct, and it's quite capable of incorporating complex and "smart" algorithms. The only constraint that Bell places on the ##\lambda## "algorithm" is that the setting at detector A is not allowed to be an input for the result at detector B, and vice versa.

It's a fun exercise (I've done it just for fun - but also google for "quantum Randi challenge") to actually code up a computer simulation in which you can plug in any functions you please to assign any values you please to any variables associated with each particle; and use any functions you please to calculate the probability of a simulated particle passing its polarizing filter. You will find yourself unable to violate the Bell inequalities.
 
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  • #29
miosim said:
I am still troubled with how Bell theorems treats the Local Hidden Variable (LHV) theories by reducing them to classical objects, like magnets, socks, boxes, etc.

J. S. Bell, “Bertlmann’s socks and the nature of reality” 1981
“.. We formulated these considerations first for pairs of socks, moving with considerable confidence in those familiar objects. But why not reason similarly for the pairs of particles of the EPR experiment? …”

My answer to this rhetorical question would be: - no, because in general we should not use the same reasoning for classical objects (socks, magnets, etc.) and for quantum entities (as LHV models are).

As you hint at just after this, Bell's reasoning isn't really about quantum entities at all. It's applied to what you actually notice in an experiment, like whether a detector ends up clicking or a certain light bulb switches on or however else it is you are recording the result. From the point of view of Bell's reasoning, any theory about such an experiment is in the end going to have to predict whether you hear that detector click or whether you see that light bulb go on. It might be the case in a certain Bell experiment that the detectors happens to look a lot like a Stern-Gerlach magnets if you open them up and it might be that you think the theoretical explanation should involve things called "spin 1/2 particles", but the way Bell gives his reasoning, those are irrelevant details.
 
  • #30
miosim said:
Eventually this “stripped to bones” LHV model was extended to All LHV models

No. What you are calling the "stripped to the bones" LHV model is not really a model at all; it's a set of properties that all possible LHV models satisfy. Hence, Bells' theorem applies to all possible LHV models. He wasn't reasoning about any specific LHV model; he was reasoning about all of them by reasoning only about properties that all of them must possess.

miosim said:
Could the correlation for such LHV model match with correlation for QM model?

No, because any such LHV model must have the properties Bell used to derive his theorem. That's the whole point of the theorem, that it must apply to any LHV model.
 
  • #31
miosim said:
in general we should not use the same reasoning for classical objects (socks, magnets, etc.) and for quantum entities

Yes.

miosim said:
(as LHV models are).

No; LHV models are not "quantum entities". That's the whole point of Bell's theorem, to show that they can't be.
 
  • #32
PeterDonis said:
he was reasoning about all of them by reasoning only about properties that all of them must possess.

PeterDonis said:
No, because any such LHV model must have the properties Bell used to derive his theorem

So what are these key properties of HV theories? As I understand, they are just a fact that values of spin, polarization, etc., are predetermined prior interacting with detector.
As I understand, the final value of spin, polarization, etc. are affected by a position of detector but we don't know much about specific mechanisms of these interactions - wave function doesn't tell us much and the results we calculate is just a guess - no experimental conformation that our HV model is correct. It is why I am not easy about jumping to calculate correlation based on simplified assumption of what HV are. They could be as wired as QM itself.

However let’s try again a simple example of HV. Say, if particle has HV that measure position of detector that “helps particle to pass”. I think that correlation for this model could be as high as we need if we can plug this “helps particle to pass” algorithm into HV.
 
  • #33
Nugatory said:
It's a fun exercise (I've done it just for fun - but also google for "quantum Randi challenge") to actually code up a computer simulation in which you can plug in any functions you please to assign any values you please to any variables associated with each particle; and use any functions you please to calculate the probability of a simulated particle passing its polarizing filter. You will find yourself unable to violate the Bell inequalities.

Is it web application? I didn't find it.
 
  • #34
miosim said:
Is it web application? I didn't find it.
"Quantum Randi challenge" should find plenty of hits. If you mean my simulation I've never posted it, as it's only a few hundred lines of Java code and writing it is 90% of the value.
 
  • #35
miosim said:
what are these key properties of HV theories? As I understand, they are just a fact that values of spin, polarization, etc., are predetermined prior interacting with detector.

No, they are that the probability distribution of measurement results at detector A cannot depend on the settings of detector B, and vice versa. That was Bell's key assumption. It is usually referred to as "locality", and is why the conclusion of the theorem applies only to "local" hidden variable theories.

Given that assumption, it doesn't matter what else determines the results at detector A: they could be predetermined, they could be sampled from a random number generator, they could depend on the phase of the moon--as long as that information is available at detector A to be taken as input at the time of measurement. (Note that detector B's settings are not available at detector A at the time of measurement if the measurements are spacelike separated.)

miosim said:
Say, if particle has HV that measure position of detector that “helps particle to pass”. I think that correlation for this model could be as high as we need if we can plug this “helps particle to pass” algorithm into HV.

I don't understand what you mean by "helps particle to pass", but as long as the algorithm for detector A does not take detector B's settings as input, and vice versa, you will be unable to produce results that violate the Bell inequalities. If you think you can, then start programming.
 
  • #36
PeterDonis

Let me think about your response.
 
  • #37
miosim said:
So what are these key properties of HV (local) theories?

PeterDonis said:
... they are that the probability distribution of measurement results at detector A cannot depend on the settings of detector B, and vice versa. That was Bell's key assumption. It is usually referred to as "locality", and is why the conclusion of the theorem applies only to "local" hidden variable theories.

Indeed the probability distribution of measurement results at detector A should not depend on the settings of detector B, and vice versa. Therefore if we rotate the first detector the probability distribution at second detectors shouldn't change. Does it contradict with the QM prediction? Does it contradict with experiment?
 
  • #38
miosim said:
Therefore if we rotate the first detector the probability distribution at second detectors shouldn't change. Does it contradict with the QM prediction?

Yes. That's what Bell showed, by showing that any probability distributions (of the results at A and B) that meet the conditions will have correlations (between the results at A and B) that satisfy the Bell inequalities. Specifically, he showed that the correlation function between A and B, if A's and B's distributions meet the conditions, must factorize into a product of a function depending only on A's settings, and a function depending only on B's settings. Then he showed that any distribution that factorizes in this way must satisfy the Bell inequalities.

The QM prediction violates the Bell inequalities, as can be shown either by just looking at the correlation function it gives and its values at various angles, or by showing that it doesn't factorize in the way described above.

miosim said:
Does it contradict with experiment?

Yes, since experiments match the QM prediction.
 
  • #39
miosim said:
Therefore if we rotate the first detector the probability distribution at second detectors shouldn't change. Does it contradict with the QM prediction? Does it contradict with experiment?

PeterDonis said:
Yes. That's what Bell showed, by showing that any probability distributions (of the results at A and B) that meet the conditions will have correlations (between the results at A and B) that satisfy the Bell inequalities

Bell's experiment is about CORRELATION between A and B. But what about measurements at one detector only. Does it depend on the position for other detector? Would the actual number of detections at detector A is changing from max to zero while we rotate detector B?
 
  • #40
miosim said:
Indeed the probability distribution of measurement results at detector A should not depend on the settings of detector B, and vice versa. Therefore if we rotate the first detector the probability distribution at second detectors shouldn't change. Does it contradict with the QM prediction? Does it contradict with experiment?

The probability distribution at the second detector does not change - every incident particle has a 50% chance of passing and a 50% chance of not passing; the experimental results at each individual detector are as random as if they had been generated by flipping coins. This is both the quantum mechanical prediction and the experimentally observed result (and If it were not, we could use entanglement to send faster-than-light messages).

However, the probability distribution of the coincidences, which only becomes apparent when Alice and Bob get together after the fact and compare notes, does change. Bell's theorem states that the quantum mechanical prediction for the coincidences can only be produced by theories in which the probability of a detection at one detector is affected by the position of and result at the other detector.

You may be finding yourself confused by the claim that the probability distribution of the detections at either detector is completely random, yet the correlations between them may not be. Here's an easy example of how that could happen: You are watching someone tossing an honest coin, and you see a random sequence of heads and tails. I am also watching someone tossing an honest coin, and I see a random sequence of heads and tails. But when we get together afterwards and compare notes, we might find that the correlation is not random; for example if we happened to be watching the same guy flipping the same coin but we were looking at different sides of the coin, the every time that I saw a heads you would see a tails and vice versa. Yet the coin flips would still be as random as random can be.
 
  • #41
Nugatory said:
The probability distribution at the second detector does not change - every incident particle has a 50% chance of passing and a 50% chance of not passing;
It is also my understanding.

Nugatory said:
You may be finding yourself confused by the claim that the probability distribution of the detections at either detector is completely random, yet the correlations between them may not be
I have no problem with this concept

Nugatory said:
Bell's theorem states that the quantum mechanical prediction for the coincidences can only be produced by theories in which the probability of a detection at one detector is affected by the position of and result at the other detector.

Another word the correlation predicted by QM is higher that any local HV theory can offer. Is it correct?
 
  • #42
miosim said:
The correlation predicted by QM is higher that any local HV theory can offer. Is it correct?

For certain arrangements of the detectors, yes. For other arrangements (such as the ones where QM predicts and experiments confirm perfect correlation or perfect anti-correlation) a local hidden variable theory could in principle produce the same results.
 
  • #43
Nugatory said:
For other arrangements (such as the ones where QM predicts and experiments confirm perfect correlation or perfect anti-correlation) a local hidden variable theory could in principle produce the same results.
Understand.I have a question:
When photon pass the detector, is the polarization of photon that passed detector and orientation of detectors matches? If they match,
does the wave function collapse first produces a photon with some polarization, and then this original polarization is rotated by detector and then pass/or_not_pass result depends on match between orientation of the detector and the original polarization of photon?
 
  • #44
Nugatory said:
Here's an easy example of how that could happen: You are watching someone tossing an honest coin, and you see a random sequence of heads and tails. I am also watching someone tossing an honest coin, and I see a random sequence of heads and tails. But when we get together afterwards and compare notes, we might find that the correlation is not random; for example if we happened to be watching the same guy flipping the same coin but we were looking at different sides of the coin, the every time that I saw a heads you would see a tails and vice versa. Yet the coin flips would still be as random as random can be.

Or to make things a bit more interesting, imagine the two of you watching someone rolling a six-sided die, but from different directions, say from the top and from one side.
 
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  • #45
jtbell said:
Or to make things a bit more interesting, imagine the two of you watching someone rolling a six-sided die, but from different directions, say from the top and from one side.
I understand these examples. I just need a better understanding of physical side of the story.
 
  • #46
miosim said:
does the wave function collapse first produces a photon with some polarization, and then this original polarization is rotated by detector and then pass/or_not_pass result depends on match between orientation of the detector and the original polarization of photon?

The best description in terms of wave function collapse says that neither particle has a definite polarization (we still have the superimposition) until one of them interacts with its detector. When this interaction happens, the particle acquires a definite polarization, either parallel to or perpendicular to the polarizer, and that's the moment of wave function collapse. The entire wave function collapses, so when the first photon acquires its definite polarization the second one immediate collapses into the corresponding state and the proceeds on to interact with its polarizer. In this model, if the first polarizer is set to angle ##\alpha## then the second photon will always interact with its polarizer as if its polarization is ##\alpha## or ##\alpha\pm\pi/2##, and this is the spooky action at a distance that you hear so much about.

But do remember that this is an explanation in terms of wave function collapse and collapse is not a fundamental part of quantum mechanics; it's just one way of interpreting the statistical predictions that the theory makes. You'll hear this interpretation a lot because it makes a sort of intuitive sense (as long as you're willing to swallow the spooky bit) and because it is a very helpful way of thinking about many single-particle problems. However, it also has some very serious conceptual problems. The most serious might be that it only makes sense if we can say that one interaction unambiguously happened before the other, and as we discussed earlier in this thread, we cannot.
 
  • #47
Nugatory said:
But do remember that this is an explanation in terms of wave function collapse and collapse is not a fundamental part of quantum mechanics; it's just one way of interpreting the statistical predictions that the theory makes. You'll hear this interpretation a lot because it makes a sort of intuitive sense (as long as you're willing to swallow the spooky bit) and because it is a very helpful way of thinking about many single-particle problems. However, it also has some very serious conceptual problems. The most serious might be that it only makes sense if we can say that one interaction unambiguously happened before the other, and as we discussed earlier in this thread, we cannot.
I understang what are you saying and will try to use the language compatible with interpretation.

Nugatory said:
In this model, if the first polarizer is set to angle α \alpha then the second photon will always interact with its polarizer as if its polarization is α \alpha or α±π/2 \alpha\pm\pi/2, and this is the spooky action at a distance that you hear so much about.

After entangled photon pass their corresponding detector/polarizers what their mutual polarization are? Do they still have polarization differences ±π/2 as entangled pair or this symmetry is distorted due to interaction with detectors?

Or may be I should ask the more general question: What is polarization of a photon that pass polarizer in reference to orientation of this polarizer?
 
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  • #48
miosim said:
Or may be I should ask the more general question: What is polarization of a photon that pass polarizer in reference to orientation of this polarizer?

Once the photon has cleared the polarizer, subsequent measurements of its polarization along that axis will yield the same result - the photon passes. (It's also no longer entangled with its partner).

In a collapse interpretation, that's because the wave function collapsed with the first interaction so now both particles are in non-superimposed polarization eigenstates. If you prefer a more ascetic interpretation, then the first measurement is a "preparation procedure" which prepares the system into a state such that a subsequent polarization measurement along that axis will be positive 100% of the time.
 
  • #49
Nugatory said:
In a collapse interpretation, that's because the wave function collapsed with the first interaction so now both particles are in non-superimposed polarization eigenstates. If you prefer a more ascetic interpretation, then the first measurement is a "preparation procedure" which prepares the system into a state such that a subsequent polarization measurement along that axis will be positive 100% of the time.

Another word the photon pair after exiting corresponding polarizer lost symmetrical polarization. It is like polarizers align photons, after they lost entanglement, to follow polarizer's orientation. It seams the "ability" of photons to follow orientation of polarizers contributes into correlation making it higher than any local HV theory can be predict.
 
  • #50
miosim said:
Another word the photon pair after exiting corresponding polarizer lost symmetrical polarization. It is like polarizers align photons, after they lost entanglement, to follow polarizer's orientation. It seams the "ability" of photons to follow orientation of polarizers contributes into correlation making it higher than any local HV theory can be predict.

Actually this language isn't compatible with description of QM system and should be reserved only for classical theories or to local HV theories.
In this case, per classical description, the predicted by QM correlation may be explained in terms of photon polarization sufficiently rotated by detector. Per local HV theory the the predicted by QM correlation may be derived from HV that measures orientation of the corresponding detector and change photon's polarization accordingly (using function similar to Malus' law). In this case there is no need for photon pair to influences each other over the distance to achieve sufficient correlation. Instead they need just "pay attention" to the orientation of local detector only.

Does it make sense?
 
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