Need Physics help with launching from angle w/ initial velocity

AI Thread Summary
To determine how far a steel ball will travel when launched at a 45° angle with an initial velocity of 3.3 m/s, the standard equations for constant acceleration in the x and y directions should be applied. The initial calculation for horizontal distance is X = 3.3cos(45)t, simplifying to X = 2.33t. The next step involves calculating the time the ball remains in the air, which requires analyzing the vertical motion. By setting the vertical displacement to zero when the ball lands, the time of flight can be determined. This approach will yield the distance from the launcher to the impact point on the floor.
astru025
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Homework Statement



You now place the launcher on the floor and shoot a steel ball at an angle of 45°. If you had previously measured an initial velocity of 3.3 m/s for this launcher, then how far from the launcher do you expect the ball to hit the floor?

Homework Equations



I can't find any equations for this problem.

The Attempt at a Solution


I tried using 45-45-90 angle method to figure out something but nothing has seemed to work. Any help/tips would be appreciated!,
 
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hi astru025! :wink:

use the standard constant acceleration equations in the x and y directions …

show us what you get :smile:​
 
Okay so I have X=3.3cos(45)t
This gets me to X=2.33t ... What do I do from hear?
 
How long does the steel ball stay in the air after launch?
 
hi astru025! :smile:

(just got up :zzz:)
astru025 said:
Okay so I have X=3.3cos(45)t
This gets me to X=2.33t ... What do I do from hear?

now do the same thing for the y direction,

then use the fact that it lands when y = 0 :wink:
 

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