Need some clarification on this limit

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The limit of (2^n)/(n^4) as n approaches infinity is indeed infinity, contrary to the initial assumption that it should be zero. The exponential growth of the numerator, 2^n, outpaces the polynomial growth of the denominator, n^4, significantly. Even small exponential bases will eventually exceed large polynomial terms as n increases. Applying l'Hôpital's rule confirms this, as repeated differentiation shows that the numerator's growth remains dominant. Therefore, the limit is correctly stated as infinity.
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I need some clarification on this limit:

lim n-->infinity of (2^n)/(n^4)

since the bottom of the function reaches infinity way faster than the top, why isn't the limit zero? my book says that it is infinity.
 
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I believe the numerator goes to infinity faster.

Take n=100, the numberator is 2100 which would be 1625, while the denominator is 1004 = 108.

I believe by applying l'Hôpital's rule, differentiate the numerator and denominator four-fold, the denominator becomes 4!, while the numerator is still factor of 2n
 
It might help to compare logarithms of the numerator and denominator.
 
UrbanXrisis said:
I need some clarification on this limit:
lim n-->infinity of (2^n)/(n^4)
since the bottom of the function reaches infinity way faster than the top, why isn't the limit zero? my book says that it is infinity.

Because the top of the function reaches infinity way faster than the bottom!

(Even 1.00001^n eventually increases faster than n^10000.)
 
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