(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two particles are located on the x axis. Particle 1 has a mass m and is at the origin. Particle 2 has a mass 2m and is at x=+L. Where on the x axis should a third particle be located so that the magnitude of the gravitational force on BOTH particles 1 and particle 2 doubles? Express your answer in terms of L.

2. Relevant equations

F = G(m1)(m2)/(r^2)

I know ur suppose to us the above equation.

3. The attempt at a solution

I have found the F between particle 1 and 2 to be = (G)(2(m)^2)/(L^2) and the F between 2 and 1 is the same magnitude but negative. So then place particle 3 on the x axis at pointX. so then now i am kind of stuck. Is the new force of particle 1 with the addition of particle 3 equal to = F btwn. particle 1 and 2 + F btwn. particle 1 and 3.

edit:also i assigned the mass of particle 3 as m2. So the mass of particle 3 is different then of particle 1 and 2.

Any help will be appreciated.

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# Homework Help: Need some help on this question

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