Need some hints for a Coulomb's Law question

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    Coulomb's law Law
AI Thread Summary
The discussion revolves around a physics homework problem involving Coulomb's Law, where a charged piece of paper is attracted to a comb. Participants clarify that to find the charge on the comb, one must calculate the gravitational force acting on the paper using w=mg, which can then be equated to the electrostatic force. The calculation of excess electrons on the comb is confirmed to be correct, with the participant arriving at approximately 1.23 x 10^12 electrons. There is a suggestion to double-check the charge calculation as it seems too large. The participant expresses gratitude for the hints received, indicating successful resolution of the problem.
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Homework Statement


Suppose that resting on your non-conducting desktop is a tiny piece of paper(m=0.08g) that carries a charge of +4 x 10-10C. You comb your hair and then slowly lower your comb until when it is 3 cm away from the paper, the paper jumps up to the comb.
a) Give an approximate value for the charge on the comb.
b) Does the comb carry an excess of electrons or protons? How many?

Homework Equations


Coulomb's Law:
F=(1/4*pi*E0)*(|Q1Q2|/r2)
Magnitude of charge of electron and proton: e=1.60217 x 10-19
Q=ne

The Attempt at a Solution


I know that we have to consider w=mg since there is mass involved for the paper. I tried to use Coulomb's Law to find the charge, but I don't know what the Force is between the two, so how can I find charge for the comb? I've converted the given numbers to the right units which are 0.08g = 0.8 x 10-4 and 3cm = 0.03m.
Now, my question is, can anyone give me a hint on how to start this question?
 
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What force is required to lift a piece of paper that has mass 0.08 grams?
 
gneill said:
What force is required to lift a piece of paper that has mass 0.08 grams?

That would be w=mg! But can I use this force as the force between the two objects? If so, I will then be able to solve for the unknown charge.

Am I on the right track?
 
whatisphysics said:
That would be w=mg! But can I use this force as the force between the two objects? If so, I will then be able to solve for the unknown charge.

Am I on the right track?

Yes, yes you are!
 
gneill said:
Yes, yes you are!

Thanks so much for the hint! Just one small question, for calculating the number of electrons(excess electrons of comb);I do Q=ne which is:

1.96x10-7C = n*1.60x10-19C
and I will get e = 1.23x1012. \leftarrowThis is the number of electrons right?

Thanks again!
 
Your unknown charge looks to be a bit large (by several orders of magnitude). Maybe you can check or show your calculation.

Your method for finding the number of electrons transferred looks fine.
 
Hey, just had to come back here to say thanks again. I asked my teacher the same question, and it turned out right!

Thanks a bunch.
 
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