What is the weight of a 1500 kg car on Planet X?

  • Thread starter Thread starter cmNickoli7
  • Start date Start date
  • Tags Tags
    Work
AI Thread Summary
The acceleration of gravity on Planet X is calculated to be approximately 5.7 m/s² based on the force required to lift a 70 kg object. Using this value, the weight of a 1500 kg car on Planet X is initially calculated as 8550 N. However, further adjustments using the formula W = m*g yield a more precise weight of approximately 8571.4 N. Despite these calculations, the website indicates the correct answer is 8565 N, suggesting a need for a slight adjustment in the value of g to 5.71 m/s². The discrepancy may stem from the website's handling of significant figures in its calculations.
cmNickoli7
Messages
1
Reaction score
0

Homework Statement



On Planet X, a 70 kg object can be lifted by a force of 400 N.

a. What is the acceleration of gravity on Planet X?

c. Suppose your car was taken to Planet X. If the car has a mass of 1500 kg, what would its weight be?

Homework Equations



some Formulas I used in solving this:

W = m*g

The Attempt at a Solution



A: W = m*g

400 = 70*g

400/70 = g

g ≈ 5.7 m/s^2

*I checked this and I know that it was correct. So, I used this in the second part of the question as my "g" *

C: W = m*g

W = 1500*5.7

W = 8550 N

*On the website, I put this in the form field and it said it was wrong, So, I got more specific.*

W = 1500*(400/70)

W ≈ 8571.4258571

W ≈ 8571.4 N

*still told me I was wrong. So i tried variations of Significant Digits (8571.43, 8571.426, 8571) all of which, the website said i was wrong. I really would like it if someone could check to make sure that I calculated it right, or if I did something wrong.*
I am teaching myself physics from this website and I am doing well. Although, it is telling me I am wrong, I am not so sure. Of course it could be an error in my calculations but I would like the help of a second pair of eyes. Thanks for taking the time to read this.

The Website Link is : http://library.thinkquest.org/10796/ch4/ch4q.htm
 
Physics news on Phys.org
cmNickoli7 said:

Homework Statement



On Planet X, a 70 kg object can be lifted by a force of 400 N.

a. What is the acceleration of gravity on Planet X?

c. Suppose your car was taken to Planet X. If the car has a mass of 1500 kg, what would its weight be?

Homework Equations



some Formulas I used in solving this:

W = m*g

The Attempt at a Solution



A: W = m*g

400 = 70*g

400/70 = g

g ≈ 5.7 m/s^2

*I checked this and I know that it was correct. So, I used this in the second part of the question as my "g" *

C: W = m*g

W = 1500*5.7

W = 8550 N

*On the website, I put this in the form field and it said it was wrong, So, I got more specific.*

W = 1500*(400/70)

W ≈ 8571.4258571

W ≈ 8571.4 N

*still told me I was wrong. So i tried variations of Significant Digits (8571.43, 8571.426, 8571) all of which, the website said i was wrong. I really would like it if someone could check to make sure that I calculated it right, or if I did something wrong.*

I am teaching myself physics from this website and I am doing well. Although, it is telling me I am wrong, I am not so sure. Of course it could be an error in my calculations but I would like the help of a second pair of eyes. Thanks for taking the time to read this.

The Website Link is : http://library.thinkquest.org/10796/ch4/ch4q.htm
Your result looks right.

Try a negative answer.
 
If you look at the source code for the web page, it actually displays the answers :smile:

The answer given is 8565N. Working back, it therefore wants you to use g = 5.71m/s2

(The number of significant figures used for the problems on this page are a bit messed up.)
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top