Net Force on Rope in Tug of War?

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In a tug of war scenario where two boys exert equal forces of 30N in opposite directions, the net force on the rope is 0N. This is because the forces cancel each other out, resulting in no acceleration of the rope. The tension in the rope, however, is 30N, as it reflects the force exerted by each boy pulling on the rope. The concept of "total tension" is misleading, as tension is defined by the opposing forces acting on the rope. Understanding these principles is crucial for accurately analyzing forces in such scenarios.
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Homework Statement


In a tug of war two boys exert an equal force of 30N. What is the nett force on the rope?


Homework Equations





The Attempt at a Solution


Since there is a tensile force on the rope will it be 30 N?

(When a spring replaces the rope it will elongate by 'x'. So the force will be kx
where k is the spring constant)
 
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The net force on the rope is calculated by summing the forces on it. Remember though, force is a vector (it has direction).
 
Be careful. Understand exactly what astrorob said: there are two boys pulling on the rope with equal "force"- but in opposite directions. What will the net force on the rope be? Another way of looking at is this: F= ma. What is the 'acceleration' of this rope? So what is the net force on it?
 
sorry to interject, but if it said find the total tension what would that be?
 
Sheneron said:
sorry to interject, but if it said find the total tension what would that be?
It would be meaningless. :wink: Asking for the tension in the rope makes sense, but "total" tension would not. A tension is created by two forces pulling in opposite directions.
 
so would the tension be 60N?
 
Sheneron said:
so would the tension be 60N?
No, just 30 N. To create a tension of 30 N requires the ends to be pulled apart by 30 N forces. The tension force is just the force that the rope exerts which must be equal and opposite to the forces that the boys exert.
 
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