Neutrino Decay Rate of the Zo Boson: Impact of Different Neutrino Types

Rothiemurchus
Messages
203
Reaction score
1
The decay rate of the Zo boson depends on the number of kinds of
neutrino.Does each kind of neutrino contribute to the decay rate equally?
Are there more electron neutrinos than muon or tau neutrinos?
 
Physics news on Phys.org
Each neutrino type contributes equally - the coupling of the Z to neutrinos is the same for all flavors, and the neutrino masses are totally negligible.
Are there more electron neutrinos than muon or tau neutrinos?
In what sense? In the universe? As produced in the Sun's core? As produced in Z decays? Clarify.
 
In open space and in z decays.
 
In Z decays: all neutrinos are equally likely to be produced. This is likely NOT tested directly, since we have a hard time producing Z's in the first place, and it's just too much to hope to detect and identify the produced neutrinos. What we do know is that the Z decays invisibly (ie. no observed end products) with some probability (~20%), which that is consistent with three species of neutrinos produced equally likely. (The theory is of course much tighter / well tested than this)

In open space: a very good question! All neutrinos produced *now* in stars are electron neutrinos, but with the advent of neutrino oscillations, that means that in free space, the composition is different. About a third of the solar neutrinos reaching Earth are electron neutrinos.

There is also an expectation that there is a "neutrino background" of origin similar to that of the CMB. Since I know very little astrophysics, I suggest asking in that forum about this background if you're interested.
 
Last edited:
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top