Vanadium 50 said:
I'm not sure I would consider KATRIN "new and important". The limit has moved down from 1.1 eV to 0.9 eV, or about 20%. But it's still an order of magnitude below the cosmological limit - that's that the sum of the neutrino masses is below 0.26 eV. (Which means a 0.09 eV upper limit on any of them)
The credible cosmology based limits are
as low as 110 meV (i.e. 0.11 eV) for the sum of the three masses, and assuming that the differences between the three neutrino masses from oscillation data are correct to within their margins of error, absolute neutrino mass boundaries can be quite tightly bounded, with the best fit value being less than that.
The difference between the first and second neutrino mass eigenstate is roughly 8.66 +/- 0.12 meV, and the difference between the second and third neutrino mass eigenstate is roughly 49.5 +/- 0.5 meV, See, e.g., the
Particle Data Group global averages.
This implies that the sum of the three neutrino mass eigenstates cannot be less than about 65.34 meV with 95% confidence, in addition to being not more than 110 meV.
Assuming the 0.11 eV sum of neutrino mass constraints, the neutrino mass differences from oscillation data, and a normal hierarchy (which almost all observational data favors, although not necessarily decisively), implies the following bounds on absolute neutrino mass, most of the uncertainty in which is driven by the uncertainty in the lightest neutrino mass which is shared in all three absolute mass estimates:
v1: 0 meV to 12 meV
v2: 8.42 meV to 21.9 meV
v3: 56.92 meV to 72.4 meV
By comparison, Katrin bounds v1 to less than 900 meV, which is 75 times the bound derived from cosmology and neutrino oscillations and an assumption of a normal mass hierarchy.
In an inverted hierarchy of neutrino masses, the minimum sum of the three neutrino masses given current neutrino oscillation data is around 98 +/- 1 meV (which leaves only about 4 meV of shared uncertainty in each of the three neutrino masses if indeed the sum of the three is not more than 110 meV), which is again, still far less than Katrin bound.