New impedance after feedback

[tanaygupta2000]

Homework Statement:

An amplifier has a voltage gain Av = 1000 , input impedance 1 kΩ and output impedance 500Ω A
fraction βv = 0.1 of the output voltage is fed back in the series in opposition to the input voltage. The
input and output impedance after the feedback are given respectively by the approximate values ?

Relevant Equations:

A' = A/(1-βA)

I know that when the feedback is connected, the voltage gain changes by the above formula. But I don't know how to find final values of input and output impedances.

 

[Gordianus]

How do input and output impedance change when you apply feedback? Have you studied that point?

 

[DaveE]

How would you measure the input impedance (i.e. what information about this circuit do you need to calculate this)? How would you measure the output impedance?
Have you drawn a schematic of this circuit yet?

 

[Gordianus]

https://www.google.com.ar/url?sa=t&...Vaw2X9cfYYw-RxEC6eCnsDt7v&cshid=1585618304450

 

[LvW]

You have mentioned a formula for the gain A´ with feedback ...when you insert the mentioned value βv = 0.1 , will the gain be larger or smaller than A (without feedback)? What do you expect ?

(By the way: An answer to your question can be found in each relevant textbook...did you already spend some time for searchnig?)