Newton's Law of Cooling Problem

AI Thread Summary
The discussion revolves around a Newton's Law of Cooling problem involving a metal bar heated in boiling water. The initial temperature of the bar is 20 degrees C, and it increases by 2 degrees per second. The correct approach involves using the differential equation for cooling, with the boiling water's temperature set at 100 degrees C. The calculations yield that it takes approximately 82.1 seconds for the bar to reach 90 degrees C and 145.7 seconds to reach 98 degrees C. The conversation highlights the importance of understanding temperature as a function of pressure in this context.
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Homework Statement



A small metal bar, whose initial temperature was 20 degrees C is dropped into a large container of boiling water. How long will it take the bar to reach 90 degrees C if it is known that its temperature increases 2 degrees in 1 second. How long will it take the bar to reach 98 degrees C?

(the back of the book gives 82.1 seconds and 145.7 seconds)

Homework Equations



\frac{dT}{dt}=k(T-Tm)

where T_m is the temperature of the surroundings.

The Attempt at a Solution



\int{\frac{1}{T-T_m}\frac{dT}{dt}dt=\int kdt

T(t)=Ce^{kt}+T_m

I'm given the points T(0)=20 and T(1)=T(0)+2=22

The problem is that this give two equations and three unknowns:

C+T_m=20

Ce^k+T_m=22

I'm given that the water is boiling, but that only gives a minimum temperature of 100 degrees celsius.
 
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Actually if the water is boiling you can be sure what the temperature is, as it will be a function of the atmospheric pressure only. Assuming the experiment is performed at the sea level, the temperature of the boiling water shall be 100 C.
 
Quiablo said:
Actually if the water is boiling you can be sure what the temperature is, as it will be a function of the atmospheric pressure only. Assuming the experiment is performed at the sea level, the temperature of the boiling water shall be 100 C.

Ok, you're right! I actually haven't taken chem yet. This is a differential equations application problem. Are you getting this from PV=nRT ?I guess if you have T=\frac{PV}{nR} I guess I can see how T is a function of pressure assuming constant volume.

I should have just tried using 100 C, because it solves the system and gives the correct function T(t)=-80e^{tln(.975)}+100 and t=82.1 gives 90 C.
 
No, no, PV = nRT is used only for (ideal) gases, and we are talking about water, a liquid that is. Indeed, the fact that water boils at 100 degrees C and no other temperature, assuming one atmospheric pressure, has to do with the fact that any substance changes its state (solid to liquid or liquid to gas or gas to liquid or liquid to solid) at a specific temperature.
 
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