Newton's Laws: Force of Tension

AI Thread Summary
The mountain climber weighs 600 N and is suspended between two cliffs by a rope, creating unequal tensions on either side due to her position. To solve for the tensions, it's important to recognize that she is in equilibrium, meaning there is no acceleration in either direction. The vertical components of the tensions must balance her weight, while the horizontal components must cancel each other out. This results in two equations with two unknowns, allowing for the calculation of the tensions in each segment of the rope. Understanding the decomposition of forces and applying these principles will lead to the correct solution.
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Homework Statement



A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 600 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope (a) to the left and (b) to the right of the mountain climber.

http://www.pitt.edu/~mis98/ch04p_102.gif

Homework Equations



Net Force = Mass * Acceleration

The Attempt at a Solution



I'm not really sure how the force of tension works. If it was one rope I could assume that all the tension was on that, but with the two ropes I'm not sure how to figure out how much each rope is holding. I attempted to decompose the force of tension but then didn't know how to find the components. I'm really lost on this problem and any help would be greatly appreciated.
 
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mcode said:

Homework Statement



A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 600 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope (a) to the left and (b) to the right of the mountain climber.

http://www.pitt.edu/~mis98/ch04p_102.gif


Homework Equations



Net Force = Mass * Acceleration


The Attempt at a Solution



I'm not really sure how the force of tension works. If it was one rope I could assume that all the tension was on that, but with the two ropes I'm not sure how to figure out how much each rope is holding. I attempted to decompose the force of tension but then didn't know how to find the components. I'm really lost on this problem and any help would be greatly appreciated.
The woman is in equilibrium. No accleration in x direction and no acceleration in y direction.
In both the ropes, tension will be along the 2 segments of the ropes. The angles at which the tensions work are given. The y components of tensions will balance the weight of the woman. and the x components will cancel out each other. Thus giving you 2 equations with two variables(Tensions in each segment). Solve it to get your answer.
 
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