Newtons Laws Question: Finding acceleration and direction of movement

AI Thread Summary
To find the acceleration of a 5.0 kg object with force components Fx= 20N and Fy= 30N, apply Newton's second law, F=ma, separately in the x and y directions. The acceleration can be calculated by dividing the force components by the mass, resulting in ax = Fx/m and ay = Fy/m. The overall acceleration can then be determined using the Pythagorean theorem, combining the x and y components. For direction, a free body diagram should be drawn, and trigonometric functions like SOH-CAH-TOA can be used to find the angle of movement. Understanding these principles is crucial for solving the problem accurately.
acorn1290
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1. The only force on a 5.0 kg object has components Fx= 20N and Fy= 30N



2. Find the acceleration of the object and its direction of movement.



3. I think I'm supposed to somehow use Soh Cah Toa inorder to find something (I don't know what this would help me find). I need to use Sin(theta)= Fx/m. But that would give me the angle measure and not the acceleration.
 
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Alright, since forces are vector quantities and the forces are acting in perpendicular directions, you can calculate the x and y components of the acceleration. After that it's merely an application of the pythagorean theorem.

For the direction, draw a free body diagram labeling the forces acting on the object and go from there. Hint: you'll need to use SOH-CAH-TOA to find the direction.
 
acorn1290 said:
1. The only force on a 5.0 kg object has components Fx= 20N and Fy= 30N



2. Find the acceleration of the object and its direction of movement.



3. I think I'm supposed to somehow use Soh Cah Toa inorder to find something (I don't know what this would help me find). I need to use Sin(theta)= Fx/m. But that would give me the angle measure and not the acceleration.
acorn1290, welcome to PF! Sin theta = Fx/m is not a correct equation, I'm not sure how you arrived at it. Are you familiar with Newton's second law? Try applying it in the x direction, and again, independently, in the y direction, and respond with your results.
 
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