Newton's Laws -- Resting hockey puck hit with a force

Click For Summary
SUMMARY

A resting hockey puck is hit with a force of 15.3 N, while experiencing a frictional force of 1.0 N. The net horizontal force acting on the puck during contact with the stick is calculated to be 14.3 N in the forward direction. After leaving the stick with a velocity of 45 m/s, the puck will travel a distance of 108 m in 3.0 seconds. The discussion emphasizes the importance of significant figures in reporting the net force, suggesting that 14.3 N is the more accurate representation.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with force and friction concepts
  • Knowledge of kinematic equations
  • Ability to perform unit conversions (e.g., grams to kilograms)
NEXT STEPS
  • Study Newton's Laws of Motion in detail
  • Learn about frictional forces and their impact on motion
  • Explore kinematic equations for uniformly accelerated motion
  • Practice problems involving significant figures in physics calculations
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of motion and forces.

Evangeline101
Messages
112
Reaction score
5

Homework Statement


A resting hockey puck is hit with a force of 15.3 N. The frictional force slowing the puck down is 1.0 N.
a) Find the net horizontal force acting on the puck while the stick is in contact with the puck.
b) If the puck leaves the stick with a velocity of 45 m/s, how far will the puck travel in 3.0 s?

Homework Equations


Fnet (h) = Fapplied + Ff
a = F/m
Δd = v1Δt + 1/2 aΔt2

The Attempt at a Solution


a) Fnet (h) = Fapplied + Ff

Fnet (h)= (15.3 N [forward]) + (1.0 N [backward ])

Fnet (h)= (15.3 N [forward]) + (-1.0 N [forward])

= 14.3 N [forward]

Fnet (h) = 14 N [forward]

c)m = 164 g = 0.164 kg

a = F/m

a = -1.0 N [forward] / 0.164 kg

a= -6.1 m/s2 [forward]

Δd = v1Δt + 1/2 aΔt2

Δd = (45 m/s) (3.0 s) + ½ (-6.1 m/s2) (3.0 s)2

Δd = 108 m (should I add a direction here, if yes then would it be 108 m [forward]?)

The puck will travel 108 m in 3.0 s.

Is this correct?
 
Physics news on Phys.org
Your work looks correct to me. I don't think you need to include a direction for the distance traveled.
 
Ok, thanks for verifying my answer :)
 
In your answer to a), why did you round to 14N?
 
I just thought I should round it to two sig-figs... is it more accurate to leave it as 14.3 N?
 
Evangeline101 said:
I just thought I should round it to two sig-figs... is it more accurate to leave it as 14.3 N?
The given data were both quoted to one decimal place, so you are justified (here) in doing so in the answer. In more complicated algebraic relationships it is not quite that simple.
 
So does that mean I should leave it at 14 N? or change it to 14.3 N?
 
Evangeline101 said:
So does that mean I should leave it at 14 N? or change it to 14.3 N?
I would submit the answer as 14.3N.
 
haruspex said:
I would submit the answer as 14.3N.

Okay, thanks for the help :)
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
5
Views
3K
Replies
21
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
13
Views
3K
Replies
15
Views
2K