Newton's Third Law Problem - Tightrope

AI Thread Summary
The problem involves calculating the tension in a rope supporting a tightrope walker who jumps with an upward acceleration. The walker has a mass of 66.0 kg and experiences a weight of 646.8 N. The tension in the rope must account for both the weight of the walker and the additional force required for his upward acceleration of 8.40 m/s². The initial attempt at a solution incorrectly calculated the tension as 7678.6 N. To find the correct tension, one must consider the upward force exerted by the rope as the walker jumps.
danshawvassar
Messages
1
Reaction score
0

Homework Statement



A 66.0 kg tightrope walker stands at the center of a rope. The rope supports are 10 m apart and the rope sags 9.00* at each end. The tightrope walker crouches down, then leaps straight up with an acceleration of 8.40 m/s2 to catch a passing trapeze.

What is the tension in the rope as he jumps?

Homework Equations



F=ma

The Attempt at a Solution



I literally have no idea how to solve this problem whatsoever. I was thinking that the y-component of the tension (T*sin(9) N) minus the weight of the man (646.8 N) is equal to the man's mass times his acceleration.

So: Tsin9 - 646.8 = 66 * 8.4
Or: T=7678.6 N

I don't think this is right though.
 
Physics news on Phys.org
welcome to pf!

hi danshawvassar! welcome to pf! :smile:

(award yourself a degree: ° :wink:)

when he straightens his legs, his centre of mass accelerates upward, so there must be a downward force by his feet on the rope, and an equal upward force by the rope on his feet

that is the force you need to find, and then find the (extra) tension that will produce that upward force :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top