Ngine running at 900 RPM to power a generator

AI Thread Summary
Running an engine at 900 RPM to power a generator requiring 1800 RPM through a pulley will halve the torque but not the horsepower, as energy transfer remains consistent. The horsepower output of the engine does not need to be doubled, despite the increased RPM requirement. The efficiency of the pulley system may affect overall performance, but the engine can still function effectively at the lower RPM. Torque is calculated using the formula Torque = Watts / (2π x revs per second), confirming that while torque decreases, horsepower remains unchanged. Overall, the setup is feasible with proper consideration of pulley efficiency.
Josh111
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I am trying to use an engine running at 900 RPM to power a generator that needs to run at 1800 RPM ( This will go through a pulley)

My question is is half the available horsepower to the generator lost since the RPM's are doubled?
In other words, do I need to double the horsepower of the engine to do this?
 
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I don't think so. The RPM's are doubled, so the torque is halved, but I think the same amount of energy will be transferred, so you will have the same horsepower. Aside from the energy lost in the pulley (depending on its efficiency), I think the same engine will still work.
 


Thanks Airman.
 


I would still like someone to back me up on that. Does it sound right to the rest of you?
 


Airman,

Yes you are correct, the faster pulley will half the torque but the motor torque will remain the same.

Torque = Watts/ (2xpi x revs per sec) in Nm

the rest of your answer is correct also.
 
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