Nickel in Coffee Cup Calorimeter (Small Error)

AI Thread Summary
The discussion revolves around calculating the specific heat capacity of nickel using a calorimetry problem involving water. The user calculated the heat transfer for water and nickel, arriving at a specific heat capacity of 3.41 J/g°C, which significantly deviates from the known value of 0.44 J/g°C for nickel. Responses suggest that the discrepancy may stem from either an error in the problem statement or a misinterpretation of the initial conditions, particularly the water's temperature. A proposed adjustment to the water's initial temperature to 23.5°C could yield a more accurate result. The conversation emphasizes the importance of verifying problem details to ensure correct calculations.
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Homework Statement



nickel weights 28.2g and is heated to 100°C
150g water at 13.5°C
After the nickel is placed in the water, the final temperature of the metal and water is 25°C.
Find the specific heat capacity of nickel

Homework Equations



Q=mcΔT


The Attempt at a Solution



Qwater=mcΔT
=150g x 4.181J/°C x (25°C-13.5°C)
=7212.225J

Qnickel+Qwater=0
Qnickel=-Qwater=-7212.225J
mcΔT=-7212.225J
c=(-7212.225J)/(28.2g)(25°C-100°C)
=3.41 J/g°C

I googled the c value for nickel and it's 0.44 at 25 degrees Celsius. I'm not sure where I went wrong. Thanks in advance for helping
 
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deezer said:
nickel weights 28.2g and is heated to 100°C
150g water at 13.5°C
After the nickel is placed in the water, the final temperature of the metal and water is 25°C.

Your result is consistent with these numbers - so it is either error in the book, or the question was asked by someone not knowing the real value, or you made a mistake copying the question.
 
Please check but I think that if the initial water temperature were 23.5° instead of the slightly odd-sounding 13.5° it comes out about right.
 
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