NMOS Common source DC-bias and gain

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The discussion focuses on calculating the DC bias and AC gain for a NMOS common source amplifier. The user determined the DC current needed from the current source to be 0.3 mA, derived from the sum of the drain currents. They also calculated the AC gain, finding it to be -10, using the transconductance formula. Confirmation was provided that the calculations for both the DC current and AC gain were accurate. The importance of accurately defining the problem was emphasized as a crucial first step in the analysis.
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Homework Statement



3PNOyHO.jpg

VOUT, they mean DC

Homework Equations


See picture, r0 is neglected also lambda (channel modulation)

The Attempt at a Solution



I calculate I DS with the formule given: 0.400*(0.5)²=0.1 mA

IOUT = 5/25000 = 0.2 mA

So the current source has got to be 0.1 + 0.2 = 0.3mA. Thats the DC current it has to be delivered right?

I also had to calculate the AC gain:

gm = K (VGS - VT) = 0.4mA/V

vin = vgs

vout / vgs = -gm * vgs * RD = -10This correct?
 
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If the thing in series with the +10V supply is indeed a current source labeled ID then you computed ID correctly.

A good first step is always to define the problem accurately.

You also have computed the ac gain correctly.
 
rude man said:
If the thing in series with the +10V supply is indeed a current source labeled ID then you computed ID correctly.

A good first step is always to define the problem accurately.

You also have computed the ac gain correctly.

Yes, I was also confused about the current source symbol. :) But it is one indeed.

Thanks for the confirmation that my calculations are correct.
 
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