No Net Force from Earth & Moon Gravity at 90% d

  • Thread starter Thread starter JorgeLuis
  • Start date Start date
  • Tags Tags
    Force Gravity
AI Thread Summary
A satellite positioned at 90% of the distance from Earth to the Moon experiences no net gravitational force due to the equal and opposite gravitational pulls from both bodies. The gravitational force can be calculated using Newton's law of universal gravitation, which states that the force is inversely proportional to the square of the distance between the two masses. At this specific point, the gravitational pull from the Earth and the Moon balances out, resulting in a net force of zero. The discussion also touches on the importance of understanding distances in gravitational calculations, particularly when determining forces acting on objects in space. A diagram illustrating these forces can aid in visualizing the problem.
JorgeLuis
Messages
3
Reaction score
0
Given that the distance between the Earth and the Moon is d = 3.84 x 10^8 m, show
that a satellite located exactly in-between the Earth and the Moon at a distance of
90% d from the Earth experiences no net force (at least when only the
gravitational force due to the Earth and the Moon at taken into account). Draw a
diagram showing the forces acting on the satellite.
 
Physics news on Phys.org
Welcome to PF.

And your attempt at the solution would be?
 
i don't even know what to do it, there was another 2 question about it which i got but i don't get this and the drawing..Help Please!
 
JorgeLuis said:
i don't even know what to do it, there was another 2 question about it which i got but i don't get this and the drawing..Help Please!

What's the equation for the force of gravity?

If there is a fixed distance between two bodies, isn't a distance to 1 from a point in between = to the fixed distance - the distance to the other?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Finding the net gravitational force on a rocket....
Replies
5
Views
2K
Calculating the Force of a Jump on the Moon
Replies
10
Views
3K
Where between the Moon and the Earth is the gravitational potential=0 ?
Replies
21
Views
3K
How Is the Net Gravity Force Calculated Between Earth, Moon, and a Rocket?
Replies
16
Views
3K
Universal Gravitation problem, help with final statement.
Replies
18
Views
2K
Earth-Moon System Homework: Net Force, Potential Energy & Escape Velocity
Replies
1
Views
4K
Space probe between the earth and moon
Replies
2
Views
1K
What force needed to launch an object from moon to Earth
Replies
14
Views
3K
What is the average force of gravity between Earth and the moon?
Replies
2
Views
2K
Calculating the Distance of a Zero Gravitational Field Between Earth and Moon
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top