We have the circuit in the figure.I have to find v using nodal analysis only.
Converted 1/6 F to -3j and 2sin2t to -2j.
The Attempt at a Solution
In node v1 we have the equation
6= -12+ [v1/2] + [( v1-v)/1]
In node v we have the equation
2j+ [(v1-v)/1]= 12 + [ v/(-3j)]
Solving these equations to find v is very easy,the crucial part is finding out if the two main equations here are correct.Are they?http://i.imgur.com/nAEsUpo.jpg