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## Homework Statement

We have the circuit in the figure.I have to find the current i using nodal analysis

## Homework Equations

1/6 F =-3j

1/2 F= -j

1/2 H= j

## The Attempt at a Solution

So we have the equations

Node V1 : [(7-V1)/(4-3j) ]=[ V1/3 ]+ [(V1-V)/-j]

Node V : [(V1-V)/-j] =(V )+ (V/j)

In the V node we multiply by j each side so we have -(V1-V)=jV+V so -V1=jV

I place this in the first node so we have

In the first node we have [(7+jV)(4+3j)]/[(4-3j)(4+3j)] = -jV/3 + [(-jV-V)/-j]

We have 1.12 +0.84j-0.16jV-0.12V=-0.33JV+V-jV

Here I find V =0.1+0.85j

Now to find i I think I need to divide this by 1/2 H so by j

Problem is ,the result in my book is i=0.75 cos2t which I don't get here so where is my mistake?