Nodal analysis with 2 voltage sources

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SUMMARY

This discussion focuses on solving a circuit with two voltage sources using nodal analysis and supernode techniques. The user seeks guidance on identifying supernodes and reference nodes, specifically under a 3-ohm resistor. A definitive approach is provided, recommending the use of superposition to analyze the circuit: first, short-circuit one voltage source to find the current and voltage, then repeat for the second source. The final results are combined to determine the overall current and voltage in the circuit.

PREREQUISITES
  • Nodal analysis in electrical circuits
  • Understanding of supernodes
  • Superposition theorem in circuit analysis
  • Basic circuit components, including resistors and voltage sources
NEXT STEPS
  • Study the principles of nodal analysis in depth
  • Learn about supernodes and their applications in circuit analysis
  • Explore the superposition theorem with practical examples
  • Practice solving circuits with multiple voltage sources
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Electrical engineering students, circuit designers, and anyone interested in mastering circuit analysis techniques, particularly those involving multiple voltage sources.

adashiu
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Can someone solve this circuit

d4bb9489359f3f85.jpg


Find v and i in the circuit.

I know that we have to make somethng with supernode, but where the supernode is here? How to develop this problem? Please help me :)

Btw it is nice forum, today i have found that. I hope I will be able to help you in other engeenering topics. Greets

My attempts:

Im not sure, but I think that reference node will be that under 3 ohm resistor ( ? ) I have no idea how to cope with a problem of 2 supernodes in this circuits ( If I am right, that there are 2 supernodes). Actually I am green... :cry:
 
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You can solve it by using superposition. Substitute one of the sources by a short circuit and solve for the other source. You find i1 and v1.
Then solve for the second source, with the first one short-circuited. You find i2 and v2.
Your solution is i = i1 + i2; v = v1 + v2.
 

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