MHB Noetherian Rings - Dummit and Foote - Chapter 15 - exercise 10

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The discussion focuses on Exercise 10 from Chapter 15 of "Abstract Algebra" by David S. Dummit and Richard M. Foote, which requires proving that the subring generated by elements of the form \(x^i y^{i-1}\) in the polynomial ring \(k[x, y]\) is not a Noetherian ring. Participants highlight the chain of ideals \(I_n = (x, xy, xy^2, \ldots, xy^n)\) to demonstrate strict inclusions, showing that \(I_n \neq I_{n-1}\) for all \(n\). This establishes that the ideal is not finitely generated, confirming the subring's non-Noetherian status.

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I am reading Dummit and Foote Chapter 15, Section 15.1: Noetherian Rings and Affine Algebraic Sets.

Exercise 10 reads as follows:

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Prove that the subring: k[x, x^2y, x^3y^2, ... ... ... \ , x^iy^{i-1} ... ... ] of the polynomial ring k[x,y] is not a Noetherian ring and hence not a finitely generated k-algebra.

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Can someone please help me get a start on this exercise.

Peter[Note: This has also been posted on MHF]
 
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It's more or less obvious that the chain of ideals should be

$$(x) \subseteq (x, xy) \subseteq (x, xy, xy^2) \subseteq (x, xy, xy^2, xy^3) \subseteq \, \cdots$$

But the strict inclusions need to be settled. Define the ideals $I_n = (x, xy, xy^2, \cdots, xy^n)$ of $k[x, xy, xy^2, \cdots ]$. Clearly, $I_0 \not = I_1$, as $xy \notin I_0$. Furthermore, $I_2 \not = I_1$ as $xy^2$ can't be written as a $k$-linear combination of $x$ and $xy$.

Can you convince yourself in this way that $I_n \not = I_{n-1}$?


Or you can just show (in the above approach) that the ideal $(x, xy, xy^2, \cdots)$ of $k[x, y]$ is not finitely generated, thus showing that $k[x, xy, xy^2, xy^3, \cdots ]$ is not finitely generated, which is equivalent to being non-Noetherian.
 

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