Non-homogenous differential Equation

sndoyle1
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Homework Statement


solve:
y""+6y'+9y=e-3x/x3


Homework Equations



y=yc+yp


The Attempt at a Solution



I found yc=C1e-3x+C2xe-3x
and am having difficulties finding yp. I am wondering which method would be the best to determine yp:

- annihilators
- undetermined coefficients
- variation of paramaters.
 
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Since it is in the form e^{ax}/x^k try using Ae^{-3x}/x
 
Thanks, it worked out. I have a hard time knowing what 'guess' to use for the derivative. How did you know to put it over x instead of x-3? I have a test tomorrow, so I want to make sure that I can do things properly.
 
I usually always try the simplest first. This doesn't pertain to this question, but if Ae^{ax} didn't work I would try Axe^{ax}, and if that didn't work I would try Ax^2e^{ax}. It can be rather tedious for some questions but eventually you start to notice patterns.
 
Is that really a fourth degree equation or is the second '' a typo?

"Undetermined coefficents" works when the right side of the equation is one of the types of solutions you can get as solutions to homogenous differential equations with constant coefficients: exponentials, sine or cosine, and polynomials, as well as combinations of those. That is not the case here. I recommend "variation of parameters".
 
I think he accidentally hit the quotation mark key.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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