Engineering Non Inverting Op-Amp Circuit Analysis

Click For Summary
SUMMARY

The discussion focuses on analyzing a non-inverting op-amp circuit with a 1V peak sinusoidal input (Vin). Key points include the importance of maintaining equal voltages at the non-inverting (+) and inverting (-) terminals for proper amplifier operation. The solution involves using nodal analysis to determine the voltages at points A and B, with the relationship V1 = VB established. The voltage divider formula is applied to find the voltage at A, leading to the calculation of Vout.

PREREQUISITES
  • Understanding of non-inverting op-amp configurations
  • Familiarity with nodal analysis in circuit theory
  • Knowledge of voltage divider principles
  • Basic operational amplifier laws and characteristics
NEXT STEPS
  • Study the principles of non-inverting op-amp circuits
  • Learn about nodal analysis techniques for circuit analysis
  • Explore voltage divider circuits and their applications
  • Review operational amplifier feedback mechanisms and their effects on gain
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of operational amplifier circuits and analysis techniques.

cavalieregi
Messages
41
Reaction score
0

Homework Statement


For an input potential (Vin ) which is a 1V (peak) sinusoidal source. Calculate V1 and Vout
upload_2014-11-6_14-49-48.png

Homework Equations


- The laws for an op-amp
- NVM

The Attempt at a Solution


Here is my attempt not sure if correct.
upload_2014-11-6_15-2-34.png
 

Attachments

  • upload_2014-11-6_14-49-27.png
    upload_2014-11-6_14-49-27.png
    9.6 KB · Views: 588
Physics news on Phys.org
VB = VA otherwise the OP-AMP is not operating as an amplifier. Fix this and you should be right.

This is a non-inverting amplifier, the input being applied to the (+) input.
 
NascentOxygen said:
VB = VA otherwise the OP-AMP is not operating as an amplifier. Fix this and you should be right.

This is a non-inverting amplifier, the input being applied to the (+) input.
Cool, just wondering why it is a negative terminal ?
 
cavalieregi said:
Cool, just wondering why it is a negative terminal ?
Why what is a negative terminal?
 
NascentOxygen said:
Why what is a negative terminal?
On diagram it has (-) for non inverting input.
 
cavalieregi said:
On diagram it has (-) for non inverting input.
(-) is the inverting input of the OP-AMP, used here for negative feedback of some output to reduce the gain from its high open-loop value. The circuit's voltage input is applied to the (+) non-inverting input of the OP-AMP.
 
  • Like
Likes cavalieregi
in addition to Nascent's points, you did some math solving for Vb incorrectly.
you say V1-Vb=0

so that means V1=Vb
why invert Vb?
 
Dont worry so much about what terminal is negative and so forth assuming this is an ideal amp.
To master op amps just stick to nodal analysis.
In this case, V1=A=B. They are all the same voltage.
We know that no current enters the op amp thru the + and - terminals.
Therefore we can easily find the voltage at A or V1 by using a simple voltage divdier. Vin X (10K/57K) = A
Now you know the voltage at B since the + and - terminals are equal in ideal amps.
Now use nodal analysis, (B / 1k) + (B - Vout)/ 10K = 0.
Solve and you are done.
 
  • Like
Likes Dhruv Dhawan and cavalieregi

Similar threads

Replies
15
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
34
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
21
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 59 ·
2
Replies
59
Views
5K