Nonuniform circular motion problem

AI Thread Summary
A 0.5kg ball swings in a vertical circle with a string length of 1.5m, and the tension at the bottom is 15 N. The user initially calculated centripetal acceleration and speed without considering the effect of gravity. It was pointed out that gravity must be included in the tension calculation, as it influences the net force acting on the ball. To solve the problem correctly, a free body diagram should be drawn to identify all forces and their resultant. Understanding the role of gravity is crucial for accurate calculations in nonuniform circular motion problems.
doctorjuice
Messages
7
Reaction score
0

Homework Statement



0.5kg ball swings in a vertical circle at the end of a 1.5m long string. When the ball is at the bottom of the circle the tension in the string is 15 N. What is the speed of the ball at that point?

Homework Equations


ac=T/m
ac=v^2/r

The Attempt at a Solution



Using the equations above, I solved for centripetal acceleration by taking the Tension (which =15N) and dividing it by the mass (0.5kg). This gave me 30 m/s^2. I next took the other equation stated above, plugged in all the numbers and solved for v, which = 6.71m/s. The answer in the back of the book was around 5.5m/s, I think. Anyway, I got the problem wrong and I can't see what I did wrong.

Any help would be greatly appreciated, I'm doing this in preparation for a test and really need to understand these problems. :smile:
 
Physics news on Phys.org
you're forgetting gravity.
 
haruspex said:
you're forgetting gravity.

Gravity would affect tension, right? If they say the tension is 15N at the bottom, aren't they including gravity?
 
doctorjuice said:
Gravity would affect tension, right? If they say the tension is 15N at the bottom, aren't they including gravity?
Yes, they are but you aren't. Draw the free body diagram. What are the forces and what is the resultant (to drive the required acceleration)?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top