Normal approximation for the proportion P hat

  • Thread starter ChrisBlack
  • Start date
  • #1
10
0

Homework Statement



68% of students favor a new policy, we are interested in the proportion of 45 students in a math class who favor the same policy.

What is the probability that the proportion of the class that favors the policy is no more than two-thirds?

Homework Equations






The Attempt at a Solution


I found the mean, .68, and the standard deviation, .047. I don't know where to take it from here though
 

Answers and Replies

  • #2
Ray Vickson
Science Advisor
Homework Helper
Dearly Missed
10,706
1,728

Homework Statement



68% of students favor a new policy, we are interested in the proportion of 45 students in a math class who favor the same policy.

What is the probability that the proportion of the class that favors the policy is no more than two-thirds?

Homework Equations






The Attempt at a Solution


I found the mean, .68, and the standard deviation, .047. I don't know where to take it from here though
If the proportion of the class in favor is no more than 2/3, what does that say about the _number_ of students in favor? What is the probability distribution of the number (out of 45) who are in favor? Note: the number in favor can be 0 or 1 or 2 or ... or 45; I am asking you to describe a formula for the probability that k students are in favor, for any of the 46 values of k. What are the mean and standard deviation of the number in favor?

Once you have dealt with these questions you will be in a better position to know what to do next.

RGV
 
  • #3
10
0
So no more than 30 students can favor it. This does not sound like anything I have done in class so far, does it have to do anything with the fact that 68% of the data falls within 2 standard deviations of the mean?
 
  • #4
Ray Vickson
Science Advisor
Homework Helper
Dearly Missed
10,706
1,728
So no more than 30 students can favor it. This does not sound like anything I have done in class so far, does it have to do anything with the fact that 68% of the data falls within 2 standard deviations of the mean?
I don't know what you have done so far, so that is why I asked the questions in my previous post. Do you know the distribution of the number if favor? Maybe you do, without even realizing it. Let's work through it slowly. Instead of asking about the number of students in 45 that are in favor, suppose instead I asked about tossing coins or dice. In fact, suppose I have a biased coin, with probability p = 0.68 of falling 'heads' in each toss. I toss it 45 times and count the resulting number of 'heads'. Do you agree this is the same problem? Have you seen before the distribution of the number of 'heads' in coin tossing?

I'll wait for your answers before continuing.

RGV
 
  • #5
10
0
Sorry for the late reply. Yes, i can see how that is the same problem and i have worked with the distribution of coin tosses. So far all I have really done is identify the variables, N (number of students, 45) P (.68), q (.32) standard deviation (.047), and mean (.68). I have to sleep so I will check back tomorrow. I really appreciate your help, thanks!
 

Related Threads on Normal approximation for the proportion P hat

Replies
19
Views
9K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
13
Views
3K
  • Last Post
Replies
4
Views
790
Replies
18
Views
516
  • Last Post
Replies
1
Views
10K
Top