Normal approximation for the proportion P hat

AI Thread Summary
The discussion centers on calculating the probability that no more than two-thirds of a math class of 45 students favor a new policy, given that 68% of students support it. Participants identify the mean as 0.68 and the standard deviation as 0.047 but express uncertainty about the next steps. The conversation emphasizes understanding the distribution of the number of students in favor, likening it to a biased coin toss scenario. It is clarified that if no more than 30 students favor the policy, this relates to the probability distribution of the number of favorable responses. The discussion concludes with a participant acknowledging their understanding of the distribution and expressing gratitude for assistance.
ChrisBlack
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Homework Statement



68% of students favor a new policy, we are interested in the proportion of 45 students in a math class who favor the same policy.

What is the probability that the proportion of the class that favors the policy is no more than two-thirds?

Homework Equations






The Attempt at a Solution


I found the mean, .68, and the standard deviation, .047. I don't know where to take it from here though
 
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ChrisBlack said:

Homework Statement



68% of students favor a new policy, we are interested in the proportion of 45 students in a math class who favor the same policy.

What is the probability that the proportion of the class that favors the policy is no more than two-thirds?

Homework Equations






The Attempt at a Solution


I found the mean, .68, and the standard deviation, .047. I don't know where to take it from here though

If the proportion of the class in favor is no more than 2/3, what does that say about the _number_ of students in favor? What is the probability distribution of the number (out of 45) who are in favor? Note: the number in favor can be 0 or 1 or 2 or ... or 45; I am asking you to describe a formula for the probability that k students are in favor, for any of the 46 values of k. What are the mean and standard deviation of the number in favor?

Once you have dealt with these questions you will be in a better position to know what to do next.

RGV
 
So no more than 30 students can favor it. This does not sound like anything I have done in class so far, does it have to do anything with the fact that 68% of the data falls within 2 standard deviations of the mean?
 
ChrisBlack said:
So no more than 30 students can favor it. This does not sound like anything I have done in class so far, does it have to do anything with the fact that 68% of the data falls within 2 standard deviations of the mean?

I don't know what you have done so far, so that is why I asked the questions in my previous post. Do you know the distribution of the number if favor? Maybe you do, without even realizing it. Let's work through it slowly. Instead of asking about the number of students in 45 that are in favor, suppose instead I asked about tossing coins or dice. In fact, suppose I have a biased coin, with probability p = 0.68 of falling 'heads' in each toss. I toss it 45 times and count the resulting number of 'heads'. Do you agree this is the same problem? Have you seen before the distribution of the number of 'heads' in coin tossing?

I'll wait for your answers before continuing.

RGV
 
Sorry for the late reply. Yes, i can see how that is the same problem and i have worked with the distribution of coin tosses. So far all I have really done is identify the variables, N (number of students, 45) P (.68), q (.32) standard deviation (.047), and mean (.68). I have to sleep so I will check back tomorrow. I really appreciate your help, thanks!
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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