Normal force as centripetal force

AI Thread Summary
The discussion revolves around determining the angular coordinate at which a particle leaves a frictionless sphere. The initial approach involves equating the normal force to the gravitational component, leading to the conclusion that the particle leaves the surface at an angle of π/2. However, there is uncertainty about whether the particle actually leaves before reaching this angle due to inertia. Participants suggest using conservation of energy to find the particle's speed at a given angle and emphasize the importance of analyzing forces in both perpendicular and tangential components. The conversation also hints at exploring alternative methods, such as kinematic approaches using polar coordinates.
Telemachus
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Homework Statement


Hi. I have this problem:

A particle of mass m, rests on top of a frictionless sphere of radius R. Admitting that part from the rest for the position indicated in the figure along a path contained in a vertical plane.
Get the value of the angular coordinate at the instant the body leaves the surface of the sphere.


attachment.php?attachmentid=28963&stc=1&d=1286746921.png


In the first place I thought: N-mg\cos\theta=0\Rightarrow{N=mg\cos\theta}
And then N=0\Leftrightarrow{mg\cos\theta=0}\Leftrightarrow{\cos\theta=0}\Leftrightarrow{\theta=\frac{\pi}{2}}

But now I'm not sure about this. I think that the angle could be before \theta=\frac{pi}{2}, because of the inertia. But I don't know how to raise the problem this way.

Bye there.
 

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The first step is finding out what the speed of the particle at an angle theta is. Conservation of energy is the easiest way to find that.

The normal force and the force of gravity must together produce the acceleration of the mass. Draw a picture of the forces involved. You can separate the forces and accelerattions in a component that is perpendicular and one that is tangential to the surface.
 
I haven't worked yet with conservation of energy, but I see what you're trying to tell me. Then just supposing that the normal force is zero when cos\theta=0 its wrong, right?

There is a "kinematic" way of doing this? with polar coordinates maybe?

Thanks for posting willem2.
 
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