Not sure where to start what formula to use

  • Thread starter Thread starter csquared
  • Start date Start date
  • Tags Tags
    Formula
Click For Summary
SUMMARY

The discussion revolves around solving a projectile motion problem involving a launch angle of 19 degrees and an initial velocity of 27 m/s. The objective is to determine the height of a building from which the projectile is launched, given that it lands 40 m from the base. Participants emphasize the importance of separating the motion into two independent components: horizontal (x-direction) and vertical (y-direction), applying the equations of constant acceleration for each direction.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with the equations of constant acceleration
  • Basic trigonometry for resolving components of motion
  • Knowledge of kinematic equations in two dimensions
NEXT STEPS
  • Study the equations of motion for projectile motion
  • Learn how to resolve vectors into horizontal and vertical components
  • Explore the concept of time of flight in projectile motion
  • Practice solving similar projectile motion problems with varying parameters
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for problem-solving strategies in kinematics.

csquared
Messages
1
Reaction score
0
my teacher gave our class this question and i just don't know what to do first, what formula doi use first?/:cry: :cry: I am going to fail!


A projectile is launched off a building at an angle of 19 degress at 27 m/s. if it lands 40 m from the base of the building, how high is the building??


please don't say the answer, i would really like to try this for myself but i just don't know what to do first.:cry:
 
Physics news on Phys.org
This will probably be moved to the homework section, this is not a forum to discuss school exercises.

Surely you have spent sometime doing constant acceleration in one dimension. This problem is not much more difficult then those, except that we have two independent directions, and so we can write the equation for constant acceleration in the x-direction and separately write the equation for constant acceleration in the y-direction.
 

Similar threads

Replies
1
Views
1K
  • · Replies 38 ·
2
Replies
38
Views
6K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
11
Views
1K
Replies
14
Views
3K
  • · Replies 5 ·
Replies
5
Views
693
Replies
2
Views
828
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 14 ·
Replies
14
Views
4K