NPN question typo or my misunderstanding

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The discussion centers on the calculation of base current (Ib) in NPN transistors. The user questions the formula provided in their book, which states Ib = (VE + 0.6V)/R1, suggesting it should instead be Ib = (Vcc - 0.6V)/R1. The user confirms that the transistor is operational, with the emitter grounded and minimal voltage drop across the collector side light bulb, indicating it is in the linear region. The confusion arises from the interpretation of voltage references in the context of NPN transistor operation.

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Ok so I'm reviewing npn transistors and here is what I am looking at

http://postimage.org/image/sdywponvv/

Now the book I bought says Ib = (VE + 0.6V)/R1
I have no idea why it would be that

Isn't it suppose to be

(Vcc -0.6V)/R1 for Ib

The transistor is definitely on as emitter is grounded
and it says that there isn't too big of a voltage drop over the collector side light bulb so it should be in linear region

So Typo or am I misunderstanding something
 
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