Number of points having integral coordinates

AI Thread Summary
The discussion revolves around finding the number of integral coordinate points within the intersection of three sets defined by complex numbers. The sets A, B, and C create a bounded area that includes points determined by specific inequalities. Initially, four integral points were identified, but upon further examination, two additional points were discovered, bringing the total to six. The importance of accurately graphing the regions and including boundary points was emphasized. Ultimately, careful analysis and visualization are crucial for solving such problems correctly.
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Homework Statement


Let A,B,C be three sets of complex numbers as defined below

A = {z:|z+1|\leq2+Re(z)}, B = {z:|z-1|\geq1} and
C=\left\{z: \frac{|z-1|}{|z+1|}\geq 1 \right\}

The number of point(s) having integral coordinates in the region A \cap B \cap C is

Homework Equations



The Attempt at a Solution


I worked out and found that A \cap B \cap C is the area bounded by the parabola y^{2}=2(x+\frac{3}{2}) and the Y-axis. So the points having integral coordinates in this region are (-1,0), (0,0), (-1,1) and (-1,-1) which counts up to 4. But the correct answer is 6.
 
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Get out a piece of graph paper and carefully graph your region. Note that boundary points are included in the given regions.
 
jambaugh said:
Get out a piece of graph paper and carefully graph your region. Note that boundary points are included in the given regions.

Ughhh... How can I miss (0,-1) and (0,1)! Thanks.
 
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