Number of ways in a 3D lattice

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Discussion Overview

The discussion centers on determining the number of paths in a lattice structure, initially in two dimensions and then extending to three dimensions and beyond. Participants explore combinatorial approaches to count paths based on the number of steps in various directions.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant, Nick, presents a method for counting paths in a 2D lattice using combinations, suggesting a formula based on the number of steps in each direction.
  • Another participant questions Nick's reasoning for the 2D case, proposing that the number of paths should be calculated as C(n+m,m), which implies a different combinatorial approach.
  • There is a suggestion that the formula for counting paths can be extended to higher dimensions, potentially involving a product of combinations.
  • Participants reference external resources, such as a video on trinomial functions, to aid in understanding the general case for counting paths in three dimensions.
  • One participant expresses a desire to refine their hints and guidance in the discussion, indicating a collaborative approach to problem-solving.

Areas of Agreement / Disagreement

There is disagreement regarding the correct approach to counting paths in the 2D case, with multiple interpretations of the combinatorial formula. The extension to higher dimensions remains unresolved, with participants exploring different possibilities.

Contextual Notes

Participants have not reached a consensus on the correct formula for the 2D case, and assumptions regarding the dimensionality and combinatorial methods are still being explored.

nickek
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Hi!
If I have points A and B in a lattice in the plane, and the closest path between them is n + m steps (for example 4 steps upwards and 5 steps to the right), there are C(9,(5-4)) = 9 combinations of paths between them. I have to choose the 4 ways upwards (or the 5 ways to the right) of the 9 total (there are just 2 possibilities in the node, so when I choose 1 of them I'm done).

But if the lattice is in the 3D space, and I have 3 choices in each node, how can I solve the number of paths in this case? E.g k + m + n = 3 steps inwards, 4 steps upwards and 5 steps tho the right. And what if we have a lattice in any dimension?

Thanks!
Nick
 
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Are you sure about the 2D case? My reasoning is that, out of the n+m steps, we have to choose the m that are upwards, so the number of paths is C(n+m,m), which is more than n+m if m>1.

My approach leads to a natural extension to the formula for the number of paths in any number of dimensions. The answer will be a product of Combinations.
 
andrewkirk said:
Are you sure about the 2D case? My reasoning is that, out of the n+m steps, we have to choose the m that are upwards, so the number of paths is C(n+m,m), which is more than n+m if m>1.

My approach leads to a natural extension to the formula for the number of paths in any number of dimensions. The answer will be a product of Combinations.
Thank you. Yes, the number of paths should be C(n+m,m).

I will think more about the extension.

Tanks again!
 
nickek said:
I will think more about the extension.
Let me know how you go. I'm still working on calibrating my hints to steer a good path between too broad (a dead giveaway) and too narrow (not much help). Sometimes that challenge seems harder than solving the problem itself!
 

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