Number of ways that seven toys can be distributed

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The problem involves distributing seven different toys to three children, with the youngest receiving three toys and the others receiving two each. The proposed solution calculates the combinations as 7 choose 3 for the youngest, followed by 4 choose 2 for one of the other children, resulting in a total of 210 ways. This method is confirmed to be correct, as reversing the order of distribution still yields the same total. The discussion emphasizes that both approaches lead to the same answer, reinforcing the validity of the calculations. The final conclusion is that the total number of ways to distribute the toys is indeed 210.
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Homework Statement


Find the number of ways in which seven different toys can be given to three children, if the youngest vis to receive three and the others two.

Homework Equations

The Attempt at a Solution


7 combination 3 × 4 combination 2 × 2 combination 2
= 210
Is this the correct way of doing this question?
 
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NihalRi said:

Homework Statement


Find the number of ways in which seven different toys can be given to three children, if the youngest vis to receive three and the others two.

Homework Equations

The Attempt at a Solution


7 combination 3 × 4 combination 2 × 2 combination 2
= 210
Is this the correct way of doing this question?

If you calculate it the other way round, starting with one of the children that gets two toys, do you get the same answer?
 
PeroK said:
If you calculate it the other way round, starting with one of the children that gets two toys, do you get the same answer?
Yes still 210, hoping this means it's right?
 
NihalRi said:
Yes still 210, hoping this means it's right?

It's a good sign! Yes, it's right!
 
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NihalRi said:

Homework Statement


Find the number of ways in which seven different toys can be given to three children, if the youngest vis to receive three and the others two.

Homework Equations

The Attempt at a Solution


7 combination 3 × 4 combination 2 × 2 combination 2
= 210
Is this the correct way of doing this question?

It is OK, but another way (maybe easier?) is: C(7,3) = number of different ways of giving the youngest 3 toys. That leaves 4 toys to be distributed, 2 each to the other two, and the number of different ways of doing that (with the given leftover four toys) is C(4,2). Altogether, the number of ways is C(7,3)*C(4,2) = 210.
 
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