Number Theory - divisibility and primes

future_phd
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Homework Statement


Prove that any integer n >= 2 such that n divides (n-1)! + 1 is prime.


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The Attempt at a Solution


I'm having trouble getting started, I have no idea how to approach this, can someone give a hint on where to begin maybe because I'm just not seeing it.
 
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Assuming that n divides (n-1) \cdot (n-2) \cdots 2 + 1. Show that this entails (n-1), (n-2), \cdots 2 do not divide n. In other words, nothing less than n divides n (except the trivial case).
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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