Number Theory Problem: Proving (a,b)=1 if a|c and b|c

yeland404
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Homework Statement



a,b,c belong to Z with (a,b)=1. Prove that if a|c and b|c, then ab|c

Homework Equations


let a1,a2...an, c belong to Zwith a1...an pairwise relatively prime, prove if ai|c for each i, then a1a2...an|c


The Attempt at a Solution



if a|c, then c=ea, b|c, then c=fb, then which the next step and how it relates with (a,b)=1
 
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(a,b)=1, thus consider the prime factorization of e.
 
There exists integers x, y such that ax+by=1. Therefore c=acx+bcy=abrx+basy.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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