An object is in free fall at the surface of the Earth. In a certain 1.0 second time interval, the average velocity of the object is measured to be 2.0 m/s downward.
What was the velocity of the object at the beginning of the 1.0 second interval?
Vavg = vi + vf / 2
The Attempt at a Solution
I came across this as i am studying for my physics final.
The answer is 2.9 m/s upward.
I am not sure how to get this because i cannot think of the right equation to use to get me to the correct answer.
Any help or hints would be greatly appreciated. Thank you