Objects and stationary observers

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When an object moves parallel to its length at a velocity approaching the speed of light, a stationary observer measures its dimensions differently. The length of the object contracts according to the formula Lseen = Loriginal * sqrt(1 - (v^2/c^2)), while the width remains unchanged. As the object's speed increases, its length appears shorter, but its width does not approach zero. This phenomenon illustrates the effects of relativistic length contraction. Understanding these concepts is crucial for grasping the implications of special relativity.
Dx
Hiya!

An object moves in a direction parallel to its length with a velocity that approaches the velocity of light. The width and length of this object, as measured by a stationary observer is what?

Can anyone gimme more insight on this problem. I am having difficulties understanding just what the hell they are talking about.
does the width approach zero while the length approaches infinity.
Dx [zz)]
 
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Only the dimension in which motion is will change, that is length.
It will get smaller by the factor Sqrt(1-(v2/c2)).
So :
Lseen by observer=Loriginal*sqrt(1-(v2/c2))

Of course, if you wait for an expert to confirm this it would be better.
 
Ok! Just to make sure I am on the right track then. The width does not change but the length approaches zero because a length of an object is measured to be shorter when its moving relative to the observer than at rest.

Yeah? I think I finally got it.

Dx :wink:
 
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