Odds of Manchester United vs Aston Villa in FA Cup 3rd Round

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Manchester United has been drawn against Aston Villa in the FA Cup 3rd round four times in the last seven draws, raising questions about the odds of this occurrence. The calculated probability of this specific matchup happening is approximately 1 in 472,216. The method involves determining the chance of drawing Villa four times and not drawing them three times, factoring in the different permutations of these outcomes. Additionally, the likelihood of any team drawing another team four times in seven draws is about 1 in 7,495, while the chance of at least one team drawing another team four times is roughly 1 in 242. These calculations highlight the rarity of such matchups in the FA Cup.
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A friend recently observed that Manchester United have been drawn against Aston Villa in The 3rd round of the FA Cup 4 times in the past 7 draws. There are 64 teams in the 3rd round draw. What are the odds of this happening?

I believe I have the answer, but I need someone to verify my answer to ensure that my understanding is correct.

So, what are the odds?
 
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Okay, obviously this is too easy a question to bother most of you. My answer was 1/472,216. Is that right?
 
Actually, I think the problem is here

I believe I have the answer, but I need someone to verify my answer to ensure that my understanding is correct.

If you want to make sure your understanding is correct, the best way is surely to post what you think the correct method would be
 
Okay.

Chance of Man U drawing Villa on one occasion A = 1/63
Chance of that not happening on same occasion B = 62/63

Chance of it happening 4 times in a row followed by 3 failures is AAAABBB=623/637.

This probability is equal to the probability of the initial condition being satisfied (that Manu draw Vill 4 times in 7), by each of the 7!/(4!*3!) = 35 different possible permeatations. Accounting for all possible solutions, the probability that the initial condition is satisfied, is 35 times 623/637 = 1/472,216.
 
Looks good to me
 
I get 35*62^3/63^7 = 1191640/562711519881, but that's close enough to your answer.

Note that the chance of Man U drawing some team 4 times out of 7 (not just Villa in particular) is 1191640/8931928887, which at roughly 1/7495 is a fair bit more likely. The chance of it happening to at least one team (not just Man U) is about 1/242. The chance of at least one team pulling some other team at least 4 times is little changed at about 1/238.
 
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