ODE Theory: General Solution to y'' + 4y' + 4y = 0

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Homework Statement



We have y'' + 4y' + 4y = 0 ; find the general solution.

Homework Equations



Reduction of Order.

The Attempt at a Solution



So when determining the roots of the characteristic equation, -2 was a double root, and therefore we can't simply have c1e-2t + c2e-2t. So I thought I would use reduction of order to get a second equation. However in the solution, they just left it c1e-2t + c2e-2t and I'm wondering if what I was taught to do in the case of non distinct roots was wrong, or if the solution is wrong.
 
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The solution appears to be wrong.

y = c1*exp(-2t) + c2 * t * exp(-2t)
 
Please show exactly what you did in your attempted reduction of order. When I try a solution of the form y= u(t)e^{-2t}, I get u(t)= A+ Bt giving y= Ae^{-2t}+ Bte^{-2t} as general solution.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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