ODE's: IVP Existence/Uniqueness

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Homework Statement



Find a nontrivial solution of the IVP

dy/dx = tx^p (p is any number); y(0) = 0

Does this violate the uniqueness part of the Existence/Uniqueness Theorem? Explain

Homework Equations


The Attempt at a Solution



I've found two solutions: one for p = 1 and one for all other cases.

It seems that having two solutions would violate the uniqueness part of the theorem. Both dy/dx and it's partial derivative of y are continuous, so the Theorem can apply, but not sure other than that.

Any help would be appreciated.
Thanks
 
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No, having different solutions for different values of t does NOT violate the theorem. With different values of p we have different differential equations. But how does 't' come into this equation? Are you sure the left isn't "dx/dt"?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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