Ohm's Law: Coaxial Cylinder Resistance & Density

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SUMMARY

This discussion focuses on calculating the resistance of coaxial conducting cylinders with varying conductivity. The inner cylinder has a radius 'a' and the outer cylinder has a radius '3a', with the region between 'a' and '2a' filled with a material of conductivity σ1, and the region between '2a' and '3a' filled with conductivity σ2. The resistance is determined using the formula R = V/I = L/(σA), where A is the surface area of the cylindrical shells. The solution involves integrating the resistance contributions of thin cylindrical shells to find the total resistance.

PREREQUISITES
  • Understanding of Ohm's Law and its applications
  • Knowledge of cylindrical coordinates and surface area calculations
  • Familiarity with the concepts of conductivity and resistivity
  • Basic integration techniques for calculating total resistance
NEXT STEPS
  • Study the derivation of resistance in cylindrical geometries
  • Learn about the relationship between conductivity and resistivity in materials
  • Explore integration techniques for calculating resistance in composite materials
  • Investigate the effects of varying conductivity on electric fields in coaxial cylinders
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Students of electrical engineering, physics enthusiasts, and anyone involved in materials science or electrical circuit design will benefit from this discussion.

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Homework Statement


Consider two coaxial conducting cylinders with radii a and 3a and length L. The region a<r<2a is filled with a material of conductivity σ1, and the region 2a<r<3a has conductivity σ2. (Assume ε12o.) The inner cylinder is held at potential V0 and the outer cylinder at V=0, so there is a radial current I.
(a) Determine the resistance.
(b) Determine the surface charge density on the boundary at r=2a.


Homework Equations


V=IR, R=pL/A, R=V/I=L/σA


The Attempt at a Solution


How do I do this? This probably is a simple problem, but I am having a hard time visualizing the path to the answer. Please help. :-)
 
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If you're given the conductivity of a material then you also have the resistivity. Imagine adding thin cylindrical shells one at a time and adding up the total resistance (i.e. there's an integration involved).

What's the resistance of a thin shell? You can calculate the surface area, you have its thickness (dr -- I did say thin!). Add 'em up!
 

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