OHM's Law-Explained to a 12yr old

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Ohm's Law can be explained using a water flow analogy, where current represents the flow of water, voltage is the height difference causing the flow, and resistance is likened to obstacles in the water's path. As the height difference increases, more water flows, similar to how higher voltage increases electrical current. Resistance slows down the flow, just as rocks and obstacles impede water movement. Increasing pressure, like increasing voltage, results in a greater flow rate. This analogy simplifies the concepts of Ohm's Law for better understanding.
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My 12 yrold is doing a report on Georg Ohm.. We have researched his life and have found the Ohm's LAw.. As much as we try to explain it to her in simple terms she doesn't understand it..(we are not knowledgeable in these subjects so we are probably not much help to her) Can anyone explain this simply to her? We appreciate it thank you very much
 
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use the analogy of a river. Resistance is like rocks and obstacles, potential difference is like the differience of height, current (the flow of electrons) is like the flow of water.

current is directly related to potential, similar to how when the height difference is great, more water flows through (faster rate). when there are obstacles, the water slow down, hence reducing the current...
 
If you push water through your showerhead with a greater pressure, more water will come out of it per unit time.

- Warren
 
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Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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