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If you have a density matrix \rho, there is a basis |\psi_j\rangle such that
\rho is diagonal in that basis. What are the conditions on \rho such that the basis that diagonalizes it is unique?
It's easy enough to work out the answer in the simplest case, of a two-dimensional basis: Then \rho can be represented as a 2x2 matrix. It will have two eigenvalues, p and q. If p = q, then \rho is diagonal in every basis. If p \neq q, then there is a unique basis (up to permutations of elements and overall phase factor) that diagonalizes \rho.
Is there some result that is similar for bases of arbitrary dimension? What's the condition on \rho such that there is a unique way to diagonalize it?
\rho is diagonal in that basis. What are the conditions on \rho such that the basis that diagonalizes it is unique?
It's easy enough to work out the answer in the simplest case, of a two-dimensional basis: Then \rho can be represented as a 2x2 matrix. It will have two eigenvalues, p and q. If p = q, then \rho is diagonal in every basis. If p \neq q, then there is a unique basis (up to permutations of elements and overall phase factor) that diagonalizes \rho.
Is there some result that is similar for bases of arbitrary dimension? What's the condition on \rho such that there is a unique way to diagonalize it?