Op-Amp Design for Vo = 12VS1+3VS2 with 50 kΩ and 25 kΩ Input Resistances

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Homework Statement


Design an op-amp circuit that can perform the operation:Vo = 12VS1+3VS2, while simultaneously presenting an input resistance of 50 kΩ on the input side for source VS1 and an input resistance of 25 kΩ on the input side for source VS2.

Homework Equations





The Attempt at a Solution


I am looking at Op-Amp gains, and I cannot find a model that will produce this output. A summation amplifier won't do it, nor a difference amplifier. What kind of model should I use?
 
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Maylis said:
A summation amplifier won't do it, nor a difference amplifier.

On what basis did you get this?
 
A summing amplifier can be non-inverting.
 
Maylis said:
None of the equations for any of the op-amps in that article seem to work with what I want.

The output is (12)V1+(3)V2. Seeing this what op-amp configuration do you think would be suitable? Forget about gains for a second.
 
Maylis said:
A Difference amplifier

"Difference" implies subtraction. Where do you see a subtraction?
 
Try to use summing amplifier + ?? amplifier
 
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the problem with the summing circuit is that Rf/50kΩ = 12 and Rf/25kΩ = 3 will not give a solution for Rf.

A non-inverting summer will have the same problem, where G is not satisfied by the two equations with the input resistances being set.
 
Does your problem put a limit on to the number of amps used?
 
So you can use summing amplifier and one voltage follower + 50K resistor between follower input the Vs1, and one non-inverting amplifier.
 
Maylis said:
the problem with the summing circuit is that Rf/50kΩ = 12 and Rf/25kΩ = 3 will not give a solution for Rf.

A non-inverting summer will have the same problem, where G is not satisfied by the two equations with the input resistances being set.
Can you pass an input through a potential divider?
 
Maylis said:
No, you can use multiple op-amps
Then it should not be difficult. You can have a unique Rf for each op-amp.