Op Amp inverting amplifier , help

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SUMMARY

The discussion centers on the calculation of output voltage in an inverting amplifier configuration using operational amplifiers (op-amps). The user initially calculated the output voltage as -1.25V but struggled with the voltage across the 10k resistor. The correct formula for calculating the current (Io) through the resistor is (Vo - Va) / 10k, where Vo is the output voltage and Va is the input voltage. The confusion arises from the understanding of potential differences in the circuit, specifically regarding the output being at a higher potential than the inverting input.

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th3plan
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http://i454.photobucket.com/albums/qq261/integralx2/opamp1.jpg

I don't understand why they did something. I found output voltage to be -1.25v , but to find voltage across the 10k resistor, its (Va-Vo)/10k am i correct? cause when i do this and try to calculate the answer for Io its not right, the book does (Vo-Va)/10k . What am i not understanding ? I did mesh or nodal analysis if i wanted something like this i always took higher potential-lower potential divided by resistor . Or maybe which I am not sure, the output is at higher potential then the invertting potential, since its being ampplified. Can someone explain please.

Thanks
 
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The voltage across the resistor is just the output voltage.
 

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