Open and Closed Pipe Length for Harmonics

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The discussion focuses on determining the necessary length and type of a pipe (open or closed) to produce harmonics at frequencies of 240Hz and 280Hz in air at 20 degrees Celsius. The fundamental frequency formula, v = λf, is mentioned, along with the relationship for harmonics in open tubes, fn = n(v/2L). It is noted that this equation applies specifically to open-ended tubes, prompting a question about the formula for closed-ended tubes. The conversation highlights the need to understand the differences in harmonic production based on the pipe's configuration. Understanding these principles is essential for solving the homework problem effectively.
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Homework Statement



a pipe in air at 20 degrees celsius ia to be designed to produce two succesive harmonics at 240Hz & 280Hz. how long must the pipe be, and is it open or closed?

Homework Equations



v=\lambdaf


The Attempt at a Solution



sorry, i could not do it. i totally can't do it.
 
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SUXinPHY said:

Homework Statement



a pipe in air at 20 degrees celsius ia to be designed to produce two succesive harmonics at 240Hz & 280Hz. how long must the pipe be, and is it open or closed?

Homework Equations



v=\lambdaf


The Attempt at a Solution



sorry, i could not do it. i totally can't do it.
Can you start by telling me what a harmonic is?
 
harmonics are frequencies of a wave which consits the fundamental frequency.

the formula for fundamental harmonic is

fn
= v/\lambdan
= n (v/2L)
= nf0
 
SUXinPHY said:
harmonics are frequencies of a wave which consits the fundamental frequency.
Correct.
SUXinPHY said:
the formula for fundamental harmonic is

fn
= v/\lambdan
= n (v/2L)
= nf0
That equation is only valid for tubes with open ends, what about tubes with closed ends?
 
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