Open Subsets of a Union: A Conjecture

pivoxa15
Messages
2,250
Reaction score
1

Homework Statement


Conjecture: If K=a union of subsets of G with K open then each subset in the union is open

The Attempt at a Solution


Can't really see the proof. In fact it's false as any non discrete topology have open sets which are a union of subsets whch may not be open.
 
Last edited:
Physics news on Phys.org
How do you expect to see the proof if you already know that the statement is false?!
 
Or consider the classic example where one takes the reunion of the non-opens sets [1/n,+infty) and get the open sets (0,+infty)
 
You can practically create a counterexample for any topology except that of the discrete topology.
 
quasar987 said:
Or consider the classic example where one takes the reunion of the non-opens sets [1/n,+infty) and get the open sets (0,+infty)

Why not just take the union of 0 and (-1,1). We get the open set (-1,1) but the point 0 is closed.
 
morphism said:
How do you expect to see the proof if you already know that the statement is false?!

After I created this thread, I realized the conjecture was false.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top