Optics Question, where is the lens

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The discussion revolves around a physics problem involving optics, specifically the placement of a lens to project an upside-down image of a 3 cm tall object located 11 m away. The focal length of the lens is 20 cm, and the user has calculated the lens placement as 0.2037 m from the wall, the image height as -1.5899 m, and the magnification as -69.999. However, there are concerns about the clarity of the answers, particularly regarding the reference points for measurements and the validity of the magnification value given the lens's proximity to the focal length. Participants emphasize the importance of sketching a ray diagram and ensuring that the calculations align logically with the physical setup.
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Homework Statement




A 3 cm tall object is placed 11 m from a wall. If the image is to be projected upside down with a 20 cm focal lense, what is:

A} The type of lens used?

B] Where is the lens placed?

C] What is the height of the image?

D] What is the magnification of the lens?




Homework Equations




1/f = 1/d_i + 1/d_o


The Attempt at a Solution



I have gotten the answers:

B] 0.2037
C] -1.5899
D] -69.999

My textbook does not supply answers, therefore I am unsure if mine are correct.

Thanks for the help,
OPO
 
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oneplusone said:

Homework Statement




A 3 cm tall object is placed 11 m from a wall. If the image is to be projected upside down with a 20 cm focal lense, what is:

A} The type of lens used?

B] Where is the lens placed?

C] What is the height of the image?

D] What is the magnification of the lens?




Homework Equations




1/f = 1/d_i + 1/d_o


The Attempt at a Solution



I have gotten the answers:

B] 0.2037
C] -1.5899
D] -69.999

My textbook does not supply answers, therefore I am unsure if mine are correct.

Thanks for the help,
OPO
Pls post your working.
 
The way to check your working in optics is to sketch out the ray diagram and see if it appears to agree.
You can also check be referencing related physics - i.e. how would you find the focal length of a lens using a very distant object? Therefore, how far should the lens be from the screen in your example (roughly)? Should it be farther or closer than that?

Note:
- the lensmakers formula usually sits the lens at x=0, and other measurements relative to this. It is not clear where your results are measured from or how you have used the formula.
- your results are meaningless without units.
 
Thanks, I have added units.
I sketched out a diagram, and ended up lettingd_i = 11 - d_odue to the problem restrictions.
oneplusone said:

Homework Statement

A 3 cm tall object is placed 11 m from a wall. If the image is to be projected upside down with a 20 cm focal lense, what is:

A} The type of lens used?

B] Where is the lens placed?

C] What is the height of the image?

D] What is the magnification of the lens?

Homework Equations

1/f = 1/d_i + 1/d_o

The Attempt at a Solution



I have gotten the answers:

B] 0.2037 m
C] -1.5899 m
D] -69.999 X

My textbook does not supply answers, therefore I am unsure if mine are correct.

Thanks for the help,
OPO
 
And your working?
 
... and where you are taking these distances from?
i.e. you wrote "B: 0.2037m" ... that does not actually answer the question does it?
If you asked, "where is the toilet?" and I said "6m" - how would you react?

The answer should look like: "The lens should be placed 20.4cm from ..." where? The screen? The object?

... and what about the other questions I asked?
... did you use your sketch to see if the answers you got made sense?
i.e. that 20.4cm is very close to the focal length. Does that make sense?
given that distance - does it make sense for the magnification to be so big?
 
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